Exercise 6. Find
the function
that
is harmonic in the first quadrant
and
has the boundary values
![[Graphics:Images/DirichletProblemModHome_gr_188.gif]](../Images/DirichletProblemModHome_gr_188.gif)
Solution 6.
See text and/or instructor's solution manual.
Answer.
, which
can be written as
.
Solution. The
transformation
maps
the first quadrant onto the upper half-plane
. Furthermore,
the segment
is
mapped onto the segment
,
the segment
is
mapped onto the segment
,
the ray
is
mapped onto the ray
,
and the ray
is
mapped onto the ray
.
This makes a new boundary value problem in the w-plane
Apply Theorem
11.2 to construct a Dirichlet solution in the upper
half-plane.
The solution in the w-plane is similar to Example
11.7.
Here we have
and
, which
we substitute into the above equation for
to
obtain
Hence the the solution in the z-plane is
Therefore,
.
Remark. For
some situations it might be useful to write this solution in the
following form
.
We are done.
Aside. We can let Mathematica double check our work.
Enter the boundary values and construct the Dirichlet form of the solution.
We are really done.
Aside. For
illustration purposes we can graph the
function
.
![[Graphics:../Images/DirichletProblemModHome_gr_215.gif]](../Images/DirichletProblemModHome_gr_215.gif)
A
contour graph of the function ![]()
where
for
.
We are really really done.
![[Graphics:../Images/DirichletProblemModHome_gr_219.gif]](../Images/DirichletProblemModHome_gr_219.gif)
A
contour graph of the function ![]()
where
for
.
![[Graphics:../Images/DirichletProblemModHome_gr_223.gif]](../Images/DirichletProblemModHome_gr_223.gif)
A
contour graph of the function ![]()
where
for
.
![[Graphics:../Images/DirichletProblemModHome_gr_227.gif]](../Images/DirichletProblemModHome_gr_227.gif)
A
graph of the function
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell