Exercise 9. Find
the function
that
is harmonic in the upper half-disk
and
has the boundary values
![[Graphics:Images/DirichletProblemModHome_gr_358.gif]](../Images/DirichletProblemModHome_gr_358.gif)
![[Graphics:Images/DirichletProblemModHome_gr_359.gif]](../Images/DirichletProblemModHome_gr_359.gif)
Solution 9.
See text and/or instructor's solution manual.
Answer. Use
the result of Example
11.9 and observe that
will be zero on the semicircle
and
on
the diameter
.
Hence the solution is
.
Solution. Use
the result of Example
11.9 and observe that
is harmonic in upper half-disk
and
has the boundary values
Hence the solution is
Therefore,
.
We are done.
A More Detailed
Solution. If more details are required,
then recall Exercise 4 in Section
10.2 where we showed that that the
transformation
maps
the upper half-disk
onto
the first quadrant
.
Furthermore, the upper
semi-circle
is
mapped onto the positive u-axis,
i.e.
,
and the diameter (or segment)
is mapped onto the positive v-axis,
i.e.
.
This makes a new boundary value problem in the first quadrant of the
w-plane
, for
, and
, for
.
Applying Example 11.2 in Section
11.1 we know that the form of the solution
is
.
Use the values
, and
and
write the system of equations
![]()
.
Simplify them and obtain
, and
.
Solving we get
and
the desired solution.
Thus,
.
Since
, the
solution
in
the z-plane in the
half-disk H will be
.
Therefore,
.
We are done.
Aside. We can let Mathematica double check our work.
We are really done.
Aside. For
illustration purposes we can graph the
function
.
![[Graphics:../Images/DirichletProblemModHome_gr_399.gif]](../Images/DirichletProblemModHome_gr_399.gif)
A
contour graph of the function ![]()
where
for
.
We are really really done.
![[Graphics:../Images/DirichletProblemModHome_gr_403.gif]](../Images/DirichletProblemModHome_gr_403.gif)
A
contour graph of the function ![]()
where
for
.
![[Graphics:../Images/DirichletProblemModHome_gr_407.gif]](../Images/DirichletProblemModHome_gr_407.gif)
A
contour graph of the function ![]()
where
for
.
![[Graphics:../Images/DirichletProblemModHome_gr_411.gif]](../Images/DirichletProblemModHome_gr_411.gif)
A
graph of the function ![]()
![[Graphics:../Images/DirichletProblemModHome_gr_413.gif]](../Images/DirichletProblemModHome_gr_413.gif)
![[Graphics:../Images/DirichletProblemModHome_gr_414.gif]](../Images/DirichletProblemModHome_gr_414.gif)
A
graph of the function ![]()
![[Graphics:../Images/DirichletProblemModHome_gr_416.gif]](../Images/DirichletProblemModHome_gr_416.gif)
![[Graphics:../Images/DirichletProblemModHome_gr_417.gif]](../Images/DirichletProblemModHome_gr_417.gif)
A
graph of the function ![]()
![[Graphics:../Images/DirichletProblemModHome_gr_419.gif]](../Images/DirichletProblemModHome_gr_419.gif)
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell