Exercise
8. Consider the conformal
mapping
.
8 (b). Find
the electrostatic potential
in
the domain D that
satisfies the boundary values, (shown in Figure
11.46)
Solution 8 (b).
See text and/or instructor's solution manual.
Answer. Use
the results of part 8 (a).
Map the given region onto the annulus
with
the mapping
,
then construct
.
Solution. The
transformation
maps
the domain D that
is the portion of the disk
,
that lies outside the circle
onto
the annulus
.
Now construct the intermediate
solution
in
the w-plane that has the boundary values
Applying Example 11.3 in Section
11.1 we know that the form of the
intermediate solution is
.
Substitute
and
get
Thus, the intermediate solution
is
.
To find the solution in the z-plane
make the substitution
.
Therefore,
,
.
We are done.
Aside. For
illustration purposes we can graph the
function
.
![[Graphics:../Images/ElectrostaticsModHome_gr_490.gif]](../Images/ElectrostaticsModHome_gr_490.gif)
A
contour graph of the function ![]()
where
for
.
We are really done.
![[Graphics:../Images/ElectrostaticsModHome_gr_494.gif]](../Images/ElectrostaticsModHome_gr_494.gif)
A
graph of the function
,
![[Graphics:../Images/ElectrostaticsModHome_gr_497.gif]](../Images/ElectrostaticsModHome_gr_497.gif)
A
graph of the function
,
![[Graphics:../Images/ElectrostaticsModHome_gr_500.gif]](../Images/ElectrostaticsModHome_gr_500.gif)
A
graph of the function
,
We are really really done.
It is possible to
expand the quantity
as
follows
.
Then
.
Therefore,
.
Aside. For
illustration purposes we can graph the
function
.
![[Graphics:../Images/ElectrostaticsModHome_gr_508.gif]](../Images/ElectrostaticsModHome_gr_508.gif)
A
contour graph of the function ![]()
where
for
.
![[Graphics:../Images/ElectrostaticsModHome_gr_512.gif]](../Images/ElectrostaticsModHome_gr_512.gif)
A
graph of the function
,
![[Graphics:../Images/ElectrostaticsModHome_gr_515.gif]](../Images/ElectrostaticsModHome_gr_515.gif)
A
graph of the function
,
![[Graphics:../Images/ElectrostaticsModHome_gr_518.gif]](../Images/ElectrostaticsModHome_gr_518.gif)
A
graph of the function
.
In
Cartesian coordinates
,
We are really really really done.
Aside. We can
graph the intermediate
solution
.
![[Graphics:../Images/ElectrostaticsModHome_gr_523.gif]](../Images/ElectrostaticsModHome_gr_523.gif)
A
contour graph of the intermediate
solution ![]()
where
for
.
![[Graphics:../Images/ElectrostaticsModHome_gr_527.gif]](../Images/ElectrostaticsModHome_gr_527.gif)
A
graph of the intermediate
solution
,
![[Graphics:../Images/ElectrostaticsModHome_gr_530.gif]](../Images/ElectrostaticsModHome_gr_530.gif)
A
graph of the intermediate
solution
,
![[Graphics:../Images/ElectrostaticsModHome_gr_533.gif]](../Images/ElectrostaticsModHome_gr_533.gif)
A
graph of the intermediate
solution
.
In
Cartesian coordinates
,
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell