Exercise 3.   Consider the ideal fluid flow in the channel bounded by the hyperbolas   [Graphics:Images/FluidFlowModHome_gr_126.gif]   and   [Graphics:Images/FluidFlowModHome_gr_127.gif]   in the first quadrant,

where the complex potential is given by   [Graphics:Images/FluidFlowModHome_gr_128.gif]   and  [Graphics:Images/FluidFlowModHome_gr_129.gif]  is a positive real number.  

3 (a).   Find the formula for speed.   Find the point on the boundary at which the speed attains a minimum value.

3 (b).   Where is the pressure greatest?

Solution 3.

See text and/or instructor's solution manual.

Solution 3 (a).   The velocity vector is   

                    [Graphics:../Images/FluidFlowModHome_gr_130.gif].  

Hence we obtain  

                    [Graphics:../Images/FluidFlowModHome_gr_131.gif].  

The minimum is will occur at the point in the channel that is closest to the origin, i. e. at the point  [Graphics:../Images/FluidFlowModHome_gr_132.gif]:  

                    [Graphics:../Images/FluidFlowModHome_gr_133.gif].  

Solution 3 (b).

      From part (a), the minimum speed occurs at the point in the channel that is closest to the origin, i. e. at the point  [Graphics:../Images/FluidFlowModHome_gr_134.gif].

The pressure is greatest where the speed is least, which occurs at the point  [Graphics:../Images/FluidFlowModHome_gr_135.gif].  

 

We are done.   

 

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/FluidFlowModHome_gr_136.gif]

[Graphics:../Images/FluidFlowModHome_gr_137.gif]

[Graphics:../Images/FluidFlowModHome_gr_138.gif]


[Graphics:../Images/FluidFlowModHome_gr_139.gif]

[Graphics:../Images/FluidFlowModHome_gr_140.gif]


[Graphics:../Images/FluidFlowModHome_gr_141.gif]

[Graphics:../Images/FluidFlowModHome_gr_142.gif]


We are really done.   

 

Aside. We can let Mathematica find the stream function.

Enter the complex potential and determine the stream function.  

[Graphics:../Images/FluidFlowModHome_gr_143.gif]

[Graphics:../Images/FluidFlowModHome_gr_144.gif]

[Graphics:../Images/FluidFlowModHome_gr_145.gif]


[Graphics:../Images/FluidFlowModHome_gr_146.gif]

[Graphics:../Images/FluidFlowModHome_gr_147.gif]

Aside.  We can make a plot of the stream function   [Graphics:../Images/FluidFlowModHome_gr_148.gif].  For illustration purposes, we choose  [Graphics:../Images/FluidFlowModHome_gr_149.gif].  

                    [Graphics:../Images/FluidFlowModHome_gr_150.gif]

                    The streamlines   [Graphics:../Images/FluidFlowModHome_gr_151.gif],     

                    for   [Graphics:../Images/FluidFlowModHome_gr_152.gif].   

                    [Graphics:../Images/FluidFlowModHome_gr_153.gif]

                    The contour graph   [Graphics:../Images/FluidFlowModHome_gr_154.gif],

                    for the constants   [Graphics:../Images/FluidFlowModHome_gr_155.gif].   

 

We are really really done.   

 

        The inverse of   [Graphics:../Images/FluidFlowModHome_gr_156.gif]   is   

                    [Graphics:../Images/FluidFlowModHome_gr_157.gif].    

                    [Graphics:../Images/FluidFlowModHome_gr_158.gif]          [Graphics:../Images/FluidFlowModHome_gr_159.gif]

                      The conformal mapping   [Graphics:../Images/FluidFlowModHome_gr_160.gif].  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell