Exercise
3. Consider the ideal fluid flow in the
channel bounded by the hyperbolas
and
in
the first quadrant,
where the complex potential is given by
and
is
a positive real number.
3 (a). Find the formula for speed. Find the point on the boundary at which the speed attains a minimum value.
3 (b). Where is the pressure greatest?
Solution 3.
See text and/or instructor's solution manual.
Solution 3
(a). The velocity vector
is
.
Hence we obtain
.
The minimum is will occur at the point in the channel that is closest
to the origin, i. e. at the point
:
.
Solution 3 (b).
From part (a), the minimum
speed occurs at the point in the channel that is closest to the
origin, i. e. at the point
.
The pressure is greatest where the speed is least, which occurs at
the point
.
We are done.
Aside. We can let Mathematica double check our work.
We are really done.
Aside. We can let Mathematica find the stream function.
Enter the complex potential and determine the stream function.
Aside. We can make
a plot of the stream function
. For
illustration purposes, we choose
.
![[Graphics:../Images/FluidFlowModHome_gr_150.gif]](../Images/FluidFlowModHome_gr_150.gif)
The
streamlines
,
for
.
![[Graphics:../Images/FluidFlowModHome_gr_153.gif]](../Images/FluidFlowModHome_gr_153.gif)
The
contour graph
,
for
the constants
.
We are really really done.
The inverse
of
is
.
![[Graphics:../Images/FluidFlowModHome_gr_159.gif]](../Images/FluidFlowModHome_gr_159.gif)
The
conformal mapping
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell