Exercise 4.   Show that the stream function is given by   [Graphics:Images/FluidFlowModHome_gr_161.gif]   for an ideal fluid flow around the angular region  

                    [Graphics:Images/FluidFlowModHome_gr_162.gif],   (as shown in Figure 11.54).   

Sketch several streamlines of the flow.  

Hint.  Use the conformal mapping   [Graphics:Images/FluidFlowModHome_gr_163.gif].  

Solution 4.

See text and/or instructor's solution manual.

      The transformation  [Graphics:../Images/FluidFlowModHome_gr_164.gif]  maps the angular region  [Graphics:../Images/FluidFlowModHome_gr_165.gif]  onto the upper half plane  [Graphics:../Images/FluidFlowModHome_gr_166.gif]  

where the complex potential is  

                    [Graphics:../Images/FluidFlowModHome_gr_167.gif].   

The complex potential in the [Graphics:../Images/FluidFlowModHome_gr_168.gif] plane is the composition  

                    [Graphics:../Images/FluidFlowModHome_gr_169.gif].   

Use polar coordinates and write this as  

                    [Graphics:../Images/FluidFlowModHome_gr_170.gif].  

Therefore the solution is  

                    [Graphics:../Images/FluidFlowModHome_gr_171.gif].  

 

We are done.   

 

Aside. We can let Mathematica find the stream function.

Enter the complex potential and determine the stream function.  

[Graphics:../Images/FluidFlowModHome_gr_172.gif]

[Graphics:../Images/FluidFlowModHome_gr_173.gif]

[Graphics:../Images/FluidFlowModHome_gr_174.gif]


[Graphics:../Images/FluidFlowModHome_gr_175.gif]

[Graphics:../Images/FluidFlowModHome_gr_176.gif]


[Graphics:../Images/FluidFlowModHome_gr_177.gif]

[Graphics:../Images/FluidFlowModHome_gr_178.gif]

Aside.  We can make a plot of the stream function   [Graphics:../Images/FluidFlowModHome_gr_179.gif].  For illustration purposes, we choose  [Graphics:../Images/FluidFlowModHome_gr_180.gif].  

                    [Graphics:../Images/FluidFlowModHome_gr_181.gif]

                    The streamlines   [Graphics:../Images/FluidFlowModHome_gr_182.gif],       

                    for    [Graphics:../Images/FluidFlowModHome_gr_183.gif].  

                    [Graphics:../Images/FluidFlowModHome_gr_184.gif]

                    The contour graph   [Graphics:../Images/FluidFlowModHome_gr_185.gif],

                    for the constants    [Graphics:../Images/FluidFlowModHome_gr_186.gif].  

 

We are really done.   

 

        The inverse of   [Graphics:../Images/FluidFlowModHome_gr_187.gif]   is   

                    [Graphics:../Images/FluidFlowModHome_gr_188.gif].    

                    [Graphics:../Images/FluidFlowModHome_gr_189.gif]          [Graphics:../Images/FluidFlowModHome_gr_190.gif]

                      The conformal mapping   [Graphics:../Images/FluidFlowModHome_gr_191.gif]   for the flow.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell