Solution 4.
See text and/or instructor's solution manual.
Answer. The
transformation
, of
Exercise 11 in Section
11.9, is known to map a horizontal flow in the upper half
plane
onto flow the upper half plane
over
the dam.
Use the details in the solution to Exercise 11 in Section
11.9, to construct the solution using the Schwarz
Christoffel formula.
The derivative is
, integration
and the boundary conditions produces
.
Furthermore, the image of horizontal streamlines in the
z-plane are curves in the
w-plane given by the parametric
equation
, for
.
Solution. Along
the x-axis use the
points
,
, and
in the w-plane
use
,
, respectively,
and let
.
The exterior angles are
,
and the formula for the derivative
is given by the Schwarz-Christoffel
formula
![[Graphics:../Images/FluidFlowImageMod_gr_160.gif]](../Images/FluidFlowImageMod_gr_160.gif)
Integrate and get
![[Graphics:../Images/FluidFlowImageMod_gr_161.gif]](../Images/FluidFlowImageMod_gr_161.gif)
The images
of
, are
, respectively.
Use
, and
obtain the system of equations
Which simplifies to be
The values
are
solutions for this system of equations.
Therefore,
.
We are done.
Aside. We can let Mathematica double check our work.
We are really done.
We can let Mathematica graph some of the streamlines.
![[Graphics:../Images/FluidFlowImageMod_gr_176.gif]](../Images/FluidFlowImageMod_gr_176.gif)
The
streamlines in the w-plane given by
the parametric equation
, for
.
We are really really done.
Aside. We can use
Mathematica to graph
.
![[Graphics:../Images/FluidFlowImageMod_gr_181.gif]](../Images/FluidFlowImageMod_gr_181.gif)
The
image of the upper half plane
under
the mapping
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell