Solution Details 12.2.
See text and/or instructor's solution manual.
Answer.
.
Alternative
Answer.
.
Solution. Find
the Fourier Series
,
by computing the coefficients with Euler's
formulae:
(12.2)
,
and
(12.3)
.
First, calculate
.
Then
Second, calculate
.
Alternately,
is
an even function so that
is
an odd function, and
for
all
.
Then Theorem
12.3 shows that
,
where the coefficients can be computed with the special
formula
.
Now calculate
Get The Answer.
Therefore,
.
We are done.
Now use the fact that
and
simplify the answer.
Therefore,
.
We are really done.
We have shown that
for
all
, and
it is easy to see that
for
all
.
Furthermore, we can express the odd
coefficients
in
the form
.
Therefore,
.
We are really really done.
Aside. We can
calculate a few terms in these series to verify that they are the
same ( up to
).
We are really done.
Aside. We can let Mathematica double check our work.
Aside. The Maple
commands are similar
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The partial lists of coefficients
and
are:
For illustration, we can sum the first few terms in these
series ( up to
).
Aside. We can
compute a few terms of the Fourier series of
using
Mathematica's built in procedure FourierTrigSeries.
.
We are really really done.
Aside. There are at
least three solutions to this problem.
We can use Mathematica to sum the infinite
series.
However, these sum might not be as familiar as those studied in
calculus.
The last expansions involve only the
and
functions.
Aside. The Maple
commands are similar
Aside. We mention
below that Landen's
Inversion Formula will permit us to write:
.
We are really really really done.
Aside. We can graph these functions to verify they are correct.
.
.
.
Remark 1. The above
formulas for
involve
the special functions
and
and
are not covered in this course.
Remark 2. A
simplification can be obtained by using Landen's
Inversion
Formula:
.
After some tedious steps
,
can be expressed as
.
.
Remark 3. Do not
worry when an unknown function such as
or
is involved in a computer computation.
There are many new and fascinating facts waiting to be revealed in
higher mathematics.
We are really really really really done.
Aside. Let us
announce that in Section
12.2 we interpret the Fourier
Series
as boundary values on the circle
,
and construct the harmonic function
inside the unit disk
with
.
The
harmonic function
, with
.

A
contour graph of the harmonic function
.
This solution is complements of the authors.
(c) 2010 John H. Mathews, Russell W. Howell