Solution Details 12.1.
See text and/or instructor's solution manual.
Answer.
.
Solution. Find
the Fourier Series
,
by computing the coefficients with Euler's
formulae:
(12.2)
,
and
(12.3)
.
First, calculate
.
Then
Second, calculate
.
Alternately,
is
an odd function so that
is
an odd function, and
for
all
.
Then Theorem
12.4 shows that
,
where the coefficients can be computed with the special
formula
.
Now calculate
Get The Answer.
Therefore,
.
We are done.
Now use the fact that
and
simplify the answer.
Therefore,
.
We are really done.
Aside. We can
calculate a few terms in these series to verify that they are the
same ( up to
).
We are really done.
Aside. We can let Mathematica double check our work.
Aside. The Maple
commands are similar
The partial lists of coefficients
and
are:
For illustration, we can sum the first few terms in these
series ( up to
).
Aside. We can
compute a few terms of the Fourier series of
using
Mathematica's built in procedure FourierTrigSeries.
.
Remark. Since
is
a point of discontinuity of
, we
know that
is
not defined at
, and
,
where
and
denote
the left-hand and right-hand limits,
respectively.
Convergence is not uniform on the closed
interval
, and
the overshooting of
is referred to as "Gibbs
phenomenon."
We are really really done.
Aside. There are at
least three solutions to this problem.
We can use Mathematica to sum the infinite
series.
However, these sum might not be as familiar as those studied in
calculus.
Aside. The Maple
commands are similar
We are really really really done.
Aside. We can graph these functions to verify they are correct.
.
.
Aside. This
expansion of
is
related to the one in Extra Example 2 where we will see that
.
It is easy to use differentiation and verify
that
.
We are really really really really done.
Aside. Let us
announce that in Section
12.2 we interpret the Fourier
Series
as boundary values on the circle
, and
construct the harmonic function
inside the unit disk
with
.

The
harmonic function
, with
.

A
contour graph of the harmonic function
.
This solution is complements of the authors.
(c) 2010 John H. Mathews, Russell W. Howell