Exercise
11.
, where
C is the line segment
from
.
Solution 11.
See text and/or instructor's solution manual.
Answer. ![]()
.
Solution. The
function
is
analytic
on the entire complex plane, except points on the negative x-axis and
at the origin,
and
is
analytic
in the right half-plane
that contains the line segment
joining
.
and
has
is
an antiderivative.
Thus, we can use Theorem
6.9 to obtain
![[Graphics:../Images/FunTheoremCalculusModHome_gr_142.gif]](../Images/FunTheoremCalculusModHome_gr_142.gif)
![[Graphics:../Images/FunTheoremCalculusModHome_gr_143.gif]](../Images/FunTheoremCalculusModHome_gr_143.gif)
The
path
of integration is the line segment
from
.
Notice
that
is
not
analytic on it's branch cut
.
We are done.
Aside. We can let Mathematica double check our work.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell