Exercise
5.
, where
C is the line
segment
.
Solution 5.
See text and/or instructor's solution manual.
Answer.
.
Solution. The
function
is
analytic
on the entire complex plane, except at the origin,
and
is
analytic
in the half plane
that contains the line segment
joining
,
and
has
is
an antiderivative.
Thus, we can use Theorem
6.9 to obtain
![[Graphics:../Images/FunTheoremCalculusModHome_gr_59.gif]](../Images/FunTheoremCalculusModHome_gr_59.gif)
![[Graphics:../Images/FunTheoremCalculusModHome_gr_60.gif]](../Images/FunTheoremCalculusModHome_gr_60.gif)
The
path
of integration is the line segment
from
.
We are done.
Aside. We can let Mathematica double check our work.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell