Exercise
7.
, where
C is the line segment
from
.
Solution 7.
See text and/or instructor's solution manual.
Answer.
.
Solution. The
function
is
analytic
on the entire complex plane, except at the origin,
and
is
analytic
in the half upper half-plane
that contains the line segment
joining
,
and
has
is
an antiderivative.
Thus, we can use Theorem
6.9 to obtain
![[Graphics:../Images/FunTheoremCalculusModHome_gr_88.gif]](../Images/FunTheoremCalculusModHome_gr_88.gif)
![[Graphics:../Images/FunTheoremCalculusModHome_gr_89.gif]](../Images/FunTheoremCalculusModHome_gr_89.gif)
The
path
of integration is the line segment
from
.
We are done.
Aside. We can let Mathematica double check our work.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell