Solution 17 (i).

See text and/or instructor's solution manual.

Solution.  To prove part (i) consider the analytic function  [Graphics:../Images/HarmonicFunctionModHome_gr_933.gif]  and it's conjugate  [Graphics:../Images/HarmonicFunctionModHome_gr_934.gif],  then

                    [Graphics:../Images/HarmonicFunctionModHome_gr_935.gif].  

Let us observe that   [Graphics:../Images/HarmonicFunctionModHome_gr_936.gif]  and then define the function  as follows:

                     [Graphics:../Images/HarmonicFunctionModHome_gr_937.gif],       and notice here that
                     
                     [Graphics:../Images/HarmonicFunctionModHome_gr_938.gif]    and    [Graphics:../Images/HarmonicFunctionModHome_gr_939.gif]).

Then we can express  [Graphics:../Images/HarmonicFunctionModHome_gr_940.gif]  in the form  

                    [Graphics:../Images/HarmonicFunctionModHome_gr_941.gif].

Now consider this as an identity in the variables  [Graphics:../Images/HarmonicFunctionModHome_gr_942.gif]:  

                    [Graphics:../Images/HarmonicFunctionModHome_gr_943.gif],  

and make the substitutions  [Graphics:../Images/HarmonicFunctionModHome_gr_944.gif],  and get  

                    [Graphics:../Images/HarmonicFunctionModHome_gr_945.gif]    

Since  [Graphics:../Images/HarmonicFunctionModHome_gr_946.gif]  we can now conclude that

                     [Graphics:../Images/HarmonicFunctionModHome_gr_947.gif]   

is a harmonic conjugate of  [Graphics:../Images/HarmonicFunctionModHome_gr_948.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell