Solution 9.
See text and/or instructor's solution manual.
Answer.
.
![[Graphics:../Images/IntegralRepresentationModHome_gr_349.gif]](../Images/IntegralRepresentationModHome_gr_349.gif)
The
point
that
lies inside the contour
.
Solution. The
integrand
is not defined at the point
which
lies interior to the circle
,
and the integral
has
the form
where
,
so we can use Cauchy's Integral formula for derivatives (see
Section
6.5).
Here we have
and
and
calculation reveals that
.
Applying Cauchy's Integral formula for
derivatives
with
we
write
.
Then multiplication by
establishes
the desired result
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell