Example
8.23. Evaluate
, where
.
![[Graphics:Images/IntegralsBranchPointsMod_gr_23.gif]](../Images/IntegralsBranchPointsMod_gr_23.gif)
Explore Solution 8.23.
Enter the function and
and
locate the isolated singularities.
![[Graphics:../Images/IntegralsBranchPointsMod_gr_30.gif]](../Images/IntegralsBranchPointsMod_gr_30.gif)
Which pole(s) are non-zero ?
![[Graphics:../Images/IntegralsBranchPointsMod_gr_32.gif]](../Images/IntegralsBranchPointsMod_gr_32.gif)
![]()
Compute the residues at
, and
use the residue calculus to compute the value of the integral.
![[Graphics:../Images/IntegralsBranchPointsMod_gr_35.gif]](../Images/IntegralsBranchPointsMod_gr_35.gif)
![[Graphics:../Images/IntegralsBranchPointsMod_gr_36.gif]](../Images/IntegralsBranchPointsMod_gr_36.gif)
![[Graphics:../Images/IntegralsBranchPointsMod_gr_37.gif]](../Images/IntegralsBranchPointsMod_gr_37.gif)
![[Graphics:../Images/IntegralsBranchPointsMod_gr_38.gif]](../Images/IntegralsBranchPointsMod_gr_38.gif)
![[Graphics:../Images/IntegralsBranchPointsMod_gr_39.gif]](../Images/IntegralsBranchPointsMod_gr_39.gif)
![[Graphics:../Images/IntegralsBranchPointsMod_gr_40.gif]](../Images/IntegralsBranchPointsMod_gr_40.gif)
Aside. We can use Mathematica's built in "PrincipalValue" option to evaluate this definite integral .
![]()
Which is also the correct answer.