9 (c). Can we
conclude that
. Justify
your answer.
Solution 9 (c).
See text and/or instructor's solution manual.
Can
not we conclude
that
, because
the integrand has the form
,
but
has
a zero of order 3 at
the origin, and does not satisfy the
hypothesis of Theorem 8.7,
which states that Q(z) must
have a zero of order at most 1 at the
origin.
We are done.
Aside. We can let Mathematica double check our work.
Note. There is no difficulty with "tail end at infinity."
However, the integrand
is
not continuous at
, so
the difficulty occurs at the origin.
For
,
, and
Hence the integral diverges.
Maple can check our work too!
>
int( x^(1/3)/(x^3*(x+1)), x=0..infinity );
![[Graphics:../Images/IntegralsBranchPointsModHome_gr_729.gif]](../Images/IntegralsBranchPointsModHome_gr_729.gif)
The
area under the curve
over
the interval
is
infinite.
![[Graphics:../Images/IntegralsBranchPointsModHome_gr_732.gif]](../Images/IntegralsBranchPointsModHome_gr_732.gif)
The
area under the curve
over
the interval
is
finite.
![[Graphics:../Images/IntegralsBranchPointsModHome_gr_735.gif]](../Images/IntegralsBranchPointsModHome_gr_735.gif)
The
area under the curve
over
the interval
is
infinite.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell