Solution 13.
See text and/or instructor's solution manual.
Answer. The
inequality
in
Jordan's Lemma would not be possible to get if we
replaced
by
either the complex
or
.
Solution.
We can still use inequality
(8-16)
(8-16)
, whenever
.
Using the result of Exercise 16 (d) in Section
5.4 we have
.
Suppose we replace
with
complex
in
the proof of Jordan's Lemma, (see Lemma
8.1) then inequality (8-16)
would become:
![]()
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If we were able to complete
this proof then we would need to show that the last quantity can be
made less than
, but
we have
![]()
![]()
![]()
.
This can be parameterized as
which
in turn can be written as
.
In the proof of Jordan's lemma
we used the inequality
and
were able to prove that
![]()
, for
.
This argument can still be
used to show that the second term
can
be made as "small as you wish."
It is curious that Mathematica can compute the
integral
analytically:
![[Graphics:../Images/IntegralsTrigImproperModHome_gr_709.gif]](../Images/IntegralsTrigImproperModHome_gr_709.gif)
The
graph of
.
We
can see that
.
This
in turn shows that
, for
.
However, there does not seem
to be a way to make the term
"as
small as you wish."
Indeed, if
then
, and
, and
![]()
.
Clearly,
as
and
it cannot be made "as small as you wish."
So there is no way to make
go
to zero as
.
This integral in
question
can
be handled by Mathematica
When we graph it, we see that it diverges to infinity and cannot be made "as small as you wish."
![[Graphics:../Images/IntegralsTrigImproperModHome_gr_728.gif]](../Images/IntegralsTrigImproperModHome_gr_728.gif)
The
graph of
.
Hence,
, as
.
This demonstration will suffice to
conclude that an analytic proof cannot be constructed when we
replace
by
with complex
.
Similarly, an analytic proof cannot be constructed when we
replace
by
with complex
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell