Solution 2 (a).
See text and/or instructor's solution manual.
Use the relations
, and
and
,
and polar coordinates
,
, and
and then get the equations
and
.
Solve these equations for
,
and
get
and
, respectively.
Use the trigonometric identity
to
eliminate
,
,
and obtain the equation of an
ellipse
.
We are done.
Aside. We can let Mathematica double check our work.
We are really done.
Aside. We can graph
the images of some circles under the
mapping
.
![[Graphics:../Images/JoukowskiTransModHome_gr_45.gif]](../Images/JoukowskiTransModHome_gr_45.gif)
The
image of the circles
, (for
), are
mapped onto the ellipses
the
ellipses
by
the Joukowski transformation
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell