Solution 3 (b).
See text and/or instructor's solution manual.
Use the inverse
and
write
Now substitute
and
in
the formula
from
part (a) and get
.
This can be simplified using the steps
, and
, and
.
It is now easy to see that
.
Therefore, the solution is the line
,
that passes through the origin.
We are done.
Aside. We can let Mathematica double check our work.
We are really done.
Aside. We can explore some graphs.
![[Graphics:../Images/JoukowskiTransModHome_gr_156.gif]](../Images/JoukowskiTransModHome_gr_156.gif)
The
image of the circle
under
the mapping
is
the line
that
passes through the origin.
![[Graphics:../Images/JoukowskiTransModHome_gr_161.gif]](../Images/JoukowskiTransModHome_gr_161.gif)
The
image of the circle
under
the mapping
is
the line
that
passes through the origin.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell