Example 4.7. Trace
out the next five iterates of Newton's method given an initial guess
of
as
a solution to the equation
, where
.
Solution. For any guess z for a solution, Newton's
method gives as the next guess the number
. Table
4.1 gives the required iterates, rounded to five decimal
places. Figure 4.2 shows the relative positions of these
points on the z plane. Note that the points
are so close together that they appear to coincide, and that the
value for
agrees to five decimal places with the actual solution
.
![[Graphics:Images/JuliaMandelbrotMod_gr_23.gif]](../Images/JuliaMandelbrotMod_gr_23.gif)
Table
4.1 The iterates of
for Newton's method applied to
.
![[Graphics:Images/JuliaMandelbrotMod_gr_26.gif]](../Images/JuliaMandelbrotMod_gr_26.gif)
Figure
4.2 The iterates of
for Newton's method applied to
.
Explore Solution 4.7.
Enter the function
and
find the next five iterates.
![[Graphics:../Images/JuliaMandelbrotMod_gr_31.gif]](../Images/JuliaMandelbrotMod_gr_31.gif)
Now compute the next five iterates
and
the corresponding values of
.
![[Graphics:../Images/JuliaMandelbrotMod_gr_35.gif]](../Images/JuliaMandelbrotMod_gr_35.gif)
Plot the iterates
and
observe that they are converging to
.
![[Graphics:../Images/JuliaMandelbrotMod_gr_39.gif]](../Images/JuliaMandelbrotMod_gr_39.gif)
![[Graphics:../Images/JuliaMandelbrotMod_gr_40.gif]](../Images/JuliaMandelbrotMod_gr_40.gif)
Notice that the points
are
co close together that they appear to coincide and that the value
for
agrees
to six decimal places with the actual solution
.