Exercise 11.  Use Theorem 4.11 and the paragraph immediately before it to show that the point  [Graphics:Images/JuliaMandelbrotModHome_gr_1023.gif]  belongs to the Mandelbrot set.  

Solution 11.

See text and/or instructor's solution manual.

If we let  [Graphics:../Images/JuliaMandelbrotModHome_gr_1024.gif],  then  

                    [Graphics:../Images/JuliaMandelbrotModHome_gr_1025.gif]  

                   [Graphics:../Images/JuliaMandelbrotModHome_gr_1026.gif]  

Hence, if   [Graphics:../Images/JuliaMandelbrotModHome_gr_1027.gif],   then   [Graphics:../Images/JuliaMandelbrotModHome_gr_1028.gif].  

Therefore, by Theorem 4.11, the point  [Graphics:../Images/JuliaMandelbrotModHome_gr_1029.gif]  belongs to the Mandelbrot set.  

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/JuliaMandelbrotModHome_gr_1030.gif]

[Graphics:../Images/JuliaMandelbrotModHome_gr_1031.gif]


[Graphics:../Images/JuliaMandelbrotModHome_gr_1032.gif]

[Graphics:../Images/JuliaMandelbrotModHome_gr_1033.gif]

We are really done.   

Aside.  We can let Mathematica explore what is happening with  [Graphics:../Images/JuliaMandelbrotModHome_gr_1034.gif].  

[Graphics:../Images/JuliaMandelbrotModHome_gr_1035.gif]


[Graphics:../Images/JuliaMandelbrotModHome_gr_1036.gif]

[Graphics:../Images/JuliaMandelbrotModHome_gr_1037.gif]

The orbit of  0  determined by   [Graphics:../Images/JuliaMandelbrotModHome_gr_1038.gif]  is bounded, hence   [Graphics:../Images/JuliaMandelbrotModHome_gr_1039.gif]   is in the Mandelbrot set.    

 


























 

This solution is complements of the authors.

 

 


























 


























 

(c) 2008 John H. Mathews, Russell W. Howell