Example
12.32. Solve the initial value
problem
with
.
![[Graphics:Images/LaplaceConvolutionMod_gr_117.gif]](../Images/LaplaceConvolutionMod_gr_117.gif)
Figure
12.31. A graph of the
solution
.
Remark. The
condition
is
not satisfied by the "solution"
. Recall
that all solutions involving the use of the Laplace transform are to
be considered zero for values of
, hence
the graph of
is given above in Figure 12.31. Note
that
has
a jump discontinuity of magnitude
at
the origin. This discontinuity occurs because either
or
must
have a jump discontinuity at the origin whenever the Dirac delta
function,
,
occurs as part of the input or driving function.
Explore Solution 12.32.
Taking transforms results in the following equation.
From a table of Laplace transforms we get
,
and the solution is
.
Aside. We can check this with Mathematica's result using the LaplaceTransform package.
![[Graphics:../Images/LaplaceConvolutionMod_gr_133.gif]](../Images/LaplaceConvolutionMod_gr_133.gif)
Aside. We use
Mathematica/s DSolve package to solve the D.E. and plot the
solution.
Notice. The initial
condition for Mathematica must be changed to
. This
is required because
.
![[Graphics:../Images/LaplaceConvolutionMod_gr_138.gif]](../Images/LaplaceConvolutionMod_gr_138.gif)