Example 12.33. Use convolution
to solve the initial value problem
with
.
![[Graphics:Images/LaplaceConvolutionMod_gr_154.gif]](../Images/LaplaceConvolutionMod_gr_154.gif)
A
graph of the solution.
Explore Solution 12.33.
The solution is accomplished in two steps.
(a) First
solve
with
.
(b) Second solve
for
with
. Then
the desired solution is
.
(a) First
solve
with
.
![[Graphics:../Images/LaplaceConvolutionMod_gr_178.gif]](../Images/LaplaceConvolutionMod_gr_178.gif)
(b) Second solve
for
with
.
The convolution theorem is used to make the construction
of
where
and
.
![[Graphics:../Images/LaplaceConvolutionMod_gr_185.gif]](../Images/LaplaceConvolutionMod_gr_185.gif)
Aside. We can substitute v[t] into the D.E.'s and verify that it is the solution.
Remark. Mathematica 4 obtained a different form of the
solution and the following comment applies when using it.
Now guide Mathematica using trigonometric
substitutions to simplify the expression
for v[t].
Notice. This cannot be
done automatically.
![[Graphics:../Images/LaplaceConvolutionMod_gr_191.gif]](../Images/LaplaceConvolutionMod_gr_191.gif)
Aside. We can substitute y[t] into the D.E.'s and verify that it is the solution.
Aside. We use Mathematica/s DSolve package to solve the D.E. and plot the solution.
Remark. This involves the version unsimplified of v[t]. So we will plot our previously simplified function y[t].
![[Graphics:../Images/LaplaceConvolutionMod_gr_199.gif]](../Images/LaplaceConvolutionMod_gr_199.gif)