Example 12.25.  Let  [Graphics:Images/LaplaceInverseMod_gr_75.gif].  Find  [Graphics:Images/LaplaceInverseMod_gr_76.gif].

Explore Solution 12.25.

Enter Y[s] and find its partial fraction expansion.

[Graphics:../Images/LaplaceInverseMod_gr_100.gif]





[Graphics:../Images/LaplaceInverseMod_gr_101.gif]



Traditionally. The partial fraction expansion can be obtained with the residue calculus.
The simple poles in the upper half plane occur at  [Graphics:../Images/LaplaceInverseMod_gr_102.gif].  First determine their residues.

[Graphics:../Images/LaplaceInverseMod_gr_103.gif]





[Graphics:../Images/LaplaceInverseMod_gr_104.gif]



Using the residue calculus, we construct the partial fraction expansion.

[Graphics:../Images/LaplaceInverseMod_gr_105.gif]





[Graphics:../Images/LaplaceInverseMod_gr_106.gif]



Use a table of Laplace transforms to solve for  [Graphics:../Images/LaplaceInverseMod_gr_107.gif].  

[Graphics:../Images/LaplaceInverseMod_gr_108.gif]




[Graphics:../Images/LaplaceInverseMod_gr_109.gif]

 

 

 

 

Aside. We can check this with Mathematica's  result using the LaplaceTransform package.

[Graphics:../Images/LaplaceInverseMod_gr_110.gif]





[Graphics:../Images/LaplaceInverseMod_gr_111.gif]



Alternately.  We could the methods of partial fraction expansion that were developed in Section 8.1.  
All we would need to do is consider complex terms in the denominator.

            [Graphics:../Images/LaplaceInverseMod_gr_112.gif]

Where

            [Graphics:../Images/LaplaceInverseMod_gr_113.gif]  

It is useful to notice that Mathematica can easily find these residues using the built in command  [Graphics:../Images/LaplaceInverseMod_gr_114.gif].

 

[Graphics:../Images/LaplaceInverseMod_gr_115.gif]


[Graphics:../Images/LaplaceInverseMod_gr_116.gif]
[Graphics:../Images/LaplaceInverseMod_gr_117.gif]


[Graphics:../Images/LaplaceInverseMod_gr_118.gif]
[Graphics:../Images/LaplaceInverseMod_gr_119.gif]


[Graphics:../Images/LaplaceInverseMod_gr_120.gif]
[Graphics:../Images/LaplaceInverseMod_gr_121.gif]


[Graphics:../Images/LaplaceInverseMod_gr_122.gif]
[Graphics:../Images/LaplaceInverseMod_gr_123.gif]

Then it is easy to form with the calculation

[Graphics:../Images/LaplaceInverseMod_gr_124.gif]





[Graphics:../Images/LaplaceInverseMod_gr_125.gif]



It takes a bit of work to collect the two fractions involving the irreducible quadratics.

[Graphics:../Images/LaplaceInverseMod_gr_126.gif]





[Graphics:../Images/LaplaceInverseMod_gr_127.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2006 John H. Mathews, Russell W. Howell