Exercise 3. Show
that
is
not a bounded function.
Solution 3.
See text and/or instructor's solution manual.
Solution.
We know that the complex cosine is an entire function that is not a
constant.
Therefore, by Theorem 6.18 (Liouville's
Theorem),
is
not bounded.
We are done.
Alternate
solution. We established this characteristic
for
with
a somewhat tedious proof in Section 5.4.
Using Identity (5-35)
gives
.
The identities
and
then
yield
(5-37)
.
If we set
in Identity (5-37) and
let
, we
get
![]()
As advertised, we have shown that
is
not a bounded function.
We are really done.
Aside. We can
graph
, this
is just for fun.
![[Graphics:../Images/LiouvilleMoreraGaussModHome_gr_111.gif]](../Images/LiouvilleMoreraGaussModHome_gr_111.gif)
The mapping
will
map the infinite strip
onto the w-plane.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell