Exercise
4. Let
.
Evaluate the following, where R represents the rectangular region
defined by the set
.
4 (c).
.
Solution 4 (c).
See text and/or instructor's solution manual.
Answer.
.
Solution. Since
we
have
.
Solutin part
(i). For
,
.
This function is increasing on the interval
, so
the maximum occurs at the right endpoint where
,
the maximum of
occurs
at
, and
.
![[Graphics:../Images/LiouvilleMoreraGaussModHome_gr_245.gif]](../Images/LiouvilleMoreraGaussModHome_gr_245.gif)
The
maximum of
on
the interval
is
.
Solutin part
(ii). For
,
.
This function is increasing on the interval
, so
the maximum occurs at the left endpoint where
,
the maximum of
occurs
at
, and
.
![[Graphics:../Images/LiouvilleMoreraGaussModHome_gr_256.gif]](../Images/LiouvilleMoreraGaussModHome_gr_256.gif)
The
maximum of
on
the interval
is
.
Solutin part
(iii). For
,
.
This function is increasing on the interval
, so
the maximum occurs at the right endpoint where
,
the maximum of
occurs
at
, and
.
![[Graphics:../Images/LiouvilleMoreraGaussModHome_gr_267.gif]](../Images/LiouvilleMoreraGaussModHome_gr_267.gif)
The
maximum of
on
the interval
is
.
Solutin part
(iv). For
,
.
This function is increasing on the interval
, so
the maximum occurs at the left endpoint where
,
the maximum of
occurs
at
, and
.
![[Graphics:../Images/LiouvilleMoreraGaussModHome_gr_278.gif]](../Images/LiouvilleMoreraGaussModHome_gr_278.gif)
The
maximum of
on
the interval
is
.
Comparing the above values
We conclude that the global maximum occurs at the
point
and
.
![[Graphics:../Images/LiouvilleMoreraGaussModHome_gr_285.gif]](../Images/LiouvilleMoreraGaussModHome_gr_285.gif)
Graph
of
over
and
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell