Exercise 13. Find
the branch of
that
maps the right half-plane
onto the right half-plane
slit
along the segment
.
Solution 13.
Answer. Use the
principal branch of the square root
.
Solution. The
desired mapping is
and
can be written as a composition
,
where
, and
,
and the principal branch of the square root
is
used.
The right
half-plane can be expressed as
The mapping
can be expressed as
,
or
and
.
Then
implies
implies
. Here
we have
.
Then
implies
implies
.
Thus, the image of
under
is
,
which is the Z-plane slit along the
ray
.
However, the mapping at hand is
and
it shifts the above region S to
the right by the amount
.
Hence,
the image of
under
is
,
which is the Z-plane slit along the
ray
.
It helps if we
observe that the image of the set
under ![]()
is the right half-plane
. However
the required image will be missing a certain segment.
Recall that the domain of
is
the Z-plane slit along the
ray
.
But our set T is the Z-plane
slit along the ray
.
So the image of T will be the right half-plane
![]()
minus the image of the segment
.
Then
implies
implies
which
in turn implies that
.
Also, we have
so
that
.
Thus, the image of the segment
under
is the segment
.
Hence,
the image of the set
under
the mapping
is the right half-plane
slit
along the segment
.
Therefore,
the image of the right half-plane
under ![]()
is the right half-plane
slit
along the segment
.
We are done.
![[Graphics:../Images/MapElementaryFunModHome_gr_739.gif]](../Images/MapElementaryFunModHome_gr_739.gif)
![[Graphics:../Images/MapElementaryFunModHome_gr_740.gif]](../Images/MapElementaryFunModHome_gr_740.gif)
The
mapping
, followed
by the mapping
.
It is easy to trace the images
of
under
the mapping ![]()
which are mapped onto the points
.
Observe
the points
and their images
and
We are really done.
Aside. If it is important then we can include the following details.
The image of the branch cut for
has
four pieces which are shown with dashed lines and rays in the
w-plane.
Notice that for
we chose
and for
we
chose
.
This requires visualizing the two values of
:
,
and depends on which half-plane you approach
, i.e.
, and
.
The point
can
be explained in more detail, and depends on which half-plane you
approach
,
this requires visualizing the two values of zero:
.
, and
.
Observe
the points
and their images
and
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell