Exercise 15. Find
the image of the sector
, under
.
Solution 15.
Answer. The
image of the sector
under
is
.
Short
Solution. The image
of
under
is
the upper half-plane
,
then the image of
under
is the
unit disk
.
Solution. The
mapping
can
be written as a composition
,
where
, and
.
The mapping
can be expressed as
,
or
and
.
Then
implies
implies
. Here
we have
.
Also,
implies
implies
.
Hence,
the image of the sector
, under
the mapping
is the upper half-plane
.
The boundary of
the upper half-plane
is
the real axis
,
and we can give the upper half-plane
a
left orientation by using the points
.
Then
maps
onto
,
which is a positive orientation for the unit
circle
.
Hence,
the image of the upper half plane
under
is
the unit disk
.
Furthermore, as a double-check we can choose the
point
in
the upper half plane
,
then
lies
in the unit disk
,
which leads us to conclude that the image region lies inside the unit
circle
.
Therefore, image
of the sector
under
is
.
We are done.
![[Graphics:../Images/MapElementaryFunModHome_gr_917.gif]](../Images/MapElementaryFunModHome_gr_917.gif)
![[Graphics:../Images/MapElementaryFunModHome_gr_918.gif]](../Images/MapElementaryFunModHome_gr_918.gif)
The
mapping
, followed
by the mapping
.
Observe
the points
and their images
and
We are really done.
Aside. If it is important then we can include the following details.
Here
the values
and
are
computed as limits.
,
.
Similarly,
the values
and
are
computed as limits.
,
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell