Exercise 7. Show
that the function
maps
the horizontal strip
onto
the region
.
Solution 7.
Answer. The
image of
under
is
.
Short
Solution. The image
of
under
is
,
then the image of
under
is
.
Solution. The
mapping
can
be written as a composition
,
where
, and
.
The horizontal strip can be expressed
as
.
The mapping
can
be written as
,
where we have
and
.
Then
implies
that
implies
that ![]()
which in turn implies that
.
Also,
implies
that
.
Hence,
the image of the horizontal strip
under
the mapping
is the the lower half-plane ![]()
The boundary of
the lower half-plane
is
the real axis
,
and we can give the lower half-plane
a
left orientation by using the points
.
Then
maps
onto
,
which is a clockwise orientation for the unit
circle
.
Hence,
the image of the lower half-plane
under
is
the region
.
Furthermore, as a double-check we can choose the
point
in
the lower half-plane
,
then
lies
in the region
,
which leads us to conclude that the image region lies outside the
unit circle
.
Therefore,
the image of the horizontal strip
under the mapping
is
the region
.
We are done.
![[Graphics:../Images/MapElementaryFunModHome_gr_275.gif]](../Images/MapElementaryFunModHome_gr_275.gif)
![[Graphics:../Images/MapElementaryFunModHome_gr_276.gif]](../Images/MapElementaryFunModHome_gr_276.gif)
The
mapping
, followed
by the mapping
.
Observe
the points
and their images
and
We are really done.
Aside. If it is important then we can include the following details.
Here
the values
and
are
calculated with limits
, and
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell