Exercise 11.  Find the image of the horizontal strip  [Graphics:Images/MapTrigonometricFunModHome_gr_769.gif]  under the mapping   [Graphics:Images/MapTrigonometricFunModHome_gr_770.gif].  

Solution 11.

Answer.   The image of the horizontal strip   [Graphics:../Images/MapTrigonometricFunModHome_gr_771.gif]   under   [Graphics:../Images/MapTrigonometricFunModHome_gr_772.gif]  

is the upper half-plane   [Graphics:../Images/MapTrigonometricFunModHome_gr_773.gif]   slit along the ray   [Graphics:../Images/MapTrigonometricFunModHome_gr_774.gif].

Hint.   Extend the results in Example 10.13.  You can use the information in Figure 10.17.

Short Solution.   Use the trigonometric identity  [Graphics:../Images/MapTrigonometricFunModHome_gr_775.gif].   

The image of the horizontal strip  [Graphics:../Images/MapTrigonometricFunModHome_gr_776.gif]  under the mapping  [Graphics:../Images/MapTrigonometricFunModHome_gr_777.gif]  is the vertical strip  

[Graphics:../Images/MapTrigonometricFunModHome_gr_778.gif].   Then the image of the vertical strip   [Graphics:../Images/MapTrigonometricFunModHome_gr_779.gif]   under the mapping   [Graphics:../Images/MapTrigonometricFunModHome_gr_780.gif]  

is the left half-plane   [Graphics:../Images/MapTrigonometricFunModHome_gr_781.gif]   slit along the ray   [Graphics:../Images/MapTrigonometricFunModHome_gr_782.gif].   Then the image of the left half-plane   

[Graphics:../Images/MapTrigonometricFunModHome_gr_783.gif]   slit along the ray   [Graphics:../Images/MapTrigonometricFunModHome_gr_784.gif]   under the mapping   [Graphics:../Images/MapTrigonometricFunModHome_gr_785.gif]   

is the upper half-plane   [Graphics:../Images/MapTrigonometricFunModHome_gr_786.gif]   slit along the ray   [Graphics:../Images/MapTrigonometricFunModHome_gr_787.gif].

Therefore, the image of the horizontal strip   [Graphics:../Images/MapTrigonometricFunModHome_gr_788.gif]   under   [Graphics:../Images/MapTrigonometricFunModHome_gr_789.gif]  

is the upper half-plane   [Graphics:../Images/MapTrigonometricFunModHome_gr_790.gif]   slit along the ray   [Graphics:../Images/MapTrigonometricFunModHome_gr_791.gif].

We might be done.   

Solution.   Use the trigonometric identity  [Graphics:../Images/MapTrigonometricFunModHome_gr_792.gif].   The mapping   [Graphics:../Images/MapTrigonometricFunModHome_gr_793.gif]   can be written as a composition  

                    [Graphics:../Images/MapTrigonometricFunModHome_gr_794.gif],    

where   

                    [Graphics:../Images/MapTrigonometricFunModHome_gr_795.gif],    

                    [Graphics:../Images/MapTrigonometricFunModHome_gr_796.gif],    and   

                    [Graphics:../Images/MapTrigonometricFunModHome_gr_797.gif].  

        Recall that the product  [Graphics:../Images/MapTrigonometricFunModHome_gr_798.gif]  rotates the plane [Graphics:../Images/MapTrigonometricFunModHome_gr_799.gif] counterclockwise about the origin.

        Hence, the image of the horizontal strip  [Graphics:../Images/MapTrigonometricFunModHome_gr_800.gif]  under the mapping  [Graphics:../Images/MapTrigonometricFunModHome_gr_801.gif]  is the vertical strip  [Graphics:../Images/MapTrigonometricFunModHome_gr_802.gif].  

        Next we can use Equation (5-33) to write  

                    [Graphics:../Images/MapTrigonometricFunModHome_gr_803.gif].  

If  [Graphics:../Images/MapTrigonometricFunModHome_gr_804.gif],  then the image of the vertical line  [Graphics:../Images/MapTrigonometricFunModHome_gr_805.gif]  is the curve in the W-plane given by the parametric equations  

                    [Graphics:../Images/MapTrigonometricFunModHome_gr_806.gif]    and    [Graphics:../Images/MapTrigonometricFunModHome_gr_807.gif],    for    [Graphics:../Images/MapTrigonometricFunModHome_gr_808.gif].  

The inequalities  [Graphics:../Images/MapTrigonometricFunModHome_gr_809.gif]  imply that the image points lie in the left half-plane  [Graphics:../Images/MapTrigonometricFunModHome_gr_810.gif].  

Eliminate Y from the parametric equations and the result is a left branch of the hyperbola   [Graphics:../Images/MapTrigonometricFunModHome_gr_811.gif].  

When [Graphics:../Images/MapTrigonometricFunModHome_gr_812.gif] the image curve approaches the V-axis where  [Graphics:../Images/MapTrigonometricFunModHome_gr_813.gif].  

When [Graphics:../Images/MapTrigonometricFunModHome_gr_814.gif] the image curve approaches the ray  [Graphics:../Images/MapTrigonometricFunModHome_gr_815.gif].  

        Hence, the image of the vertical strip  [Graphics:../Images/MapTrigonometricFunModHome_gr_816.gif]  under the mapping  [Graphics:../Images/MapTrigonometricFunModHome_gr_817.gif]  

is the left half-plane  [Graphics:../Images/MapTrigonometricFunModHome_gr_818.gif]  slit along the ray  [Graphics:../Images/MapTrigonometricFunModHome_gr_819.gif] .

        Recall that the product  [Graphics:../Images/MapTrigonometricFunModHome_gr_820.gif]  rotates the plane [Graphics:../Images/MapTrigonometricFunModHome_gr_821.gif] clockwise about the origin.

        Hence, the image of the left half-plane   [Graphics:../Images/MapTrigonometricFunModHome_gr_822.gif]  slit along the ray   [Graphics:../Images/MapTrigonometricFunModHome_gr_823.gif]
        
under the mapping   [Graphics:../Images/MapTrigonometricFunModHome_gr_824.gif]   is the upper half-plane   [Graphics:../Images/MapTrigonometricFunModHome_gr_825.gif]   slit along the ray   [Graphics:../Images/MapTrigonometricFunModHome_gr_826.gif].

        Therefore, the image of the horizontal strip   [Graphics:../Images/MapTrigonometricFunModHome_gr_827.gif]   under the mapping   [Graphics:../Images/MapTrigonometricFunModHome_gr_828.gif]  

is the upper half-plane   [Graphics:../Images/MapTrigonometricFunModHome_gr_829.gif]   slit along the ray   [Graphics:../Images/MapTrigonometricFunModHome_gr_830.gif].

We are done.   

Aside.  We can look at some graphs of the mapping  [Graphics:../Images/MapTrigonometricFunModHome_gr_831.gif].

 

          [Graphics:../Images/MapTrigonometricFunModHome_gr_832.gif]          [Graphics:../Images/MapTrigonometricFunModHome_gr_833.gif]

  

          [Graphics:../Images/MapTrigonometricFunModHome_gr_834.gif]          [Graphics:../Images/MapTrigonometricFunModHome_gr_835.gif]

            The mapping  [Graphics:../Images/MapTrigonometricFunModHome_gr_840.gif],  followed by  [Graphics:../Images/MapTrigonometricFunModHome_gr_841.gif],  followed by  [Graphics:../Images/MapTrigonometricFunModHome_gr_842.gif].  

          [Graphics:../Images/MapTrigonometricFunModHome_gr_836.gif]          [Graphics:../Images/MapTrigonometricFunModHome_gr_837.gif]

          [Graphics:../Images/MapTrigonometricFunModHome_gr_838.gif]          [Graphics:../Images/MapTrigonometricFunModHome_gr_839.gif]

          The mapping  [Graphics:../Images/MapTrigonometricFunModHome_gr_840.gif],  followed by  [Graphics:../Images/MapTrigonometricFunModHome_gr_841.gif],  followed by  [Graphics:../Images/MapTrigonometricFunModHome_gr_842.gif].  

          Observe the points [Graphics:../Images/MapTrigonometricFunModHome_gr_843.gif] and their images  [Graphics:../Images/MapTrigonometricFunModHome_gr_844.gif]  and  [Graphics:../Images/MapTrigonometricFunModHome_gr_845.gif]  

[Graphics:../Images/MapTrigonometricFunModHome_gr_846.gif]          [Graphics:../Images/MapTrigonometricFunModHome_gr_847.gif]          [Graphics:../Images/MapTrigonometricFunModHome_gr_848.gif]          [Graphics:../Images/MapTrigonometricFunModHome_gr_849.gif]  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell