Exercise 7 (b).  Find   [Graphics:Images/MapTrigonometricFunModHome_gr_465.gif].  

Solution 7 (b).

Answer.   [Graphics:../Images/MapTrigonometricFunModHome_gr_466.gif].  

Solution.  Recall that   [Graphics:../Images/MapTrigonometricFunModHome_gr_467.gif]   so that

                    [Graphics:../Images/MapTrigonometricFunModHome_gr_468.gif].

Since   [Graphics:../Images/MapTrigonometricFunModHome_gr_469.gif]    and    [Graphics:../Images/MapTrigonometricFunModHome_gr_470.gif]   we have

                    [Graphics:../Images/MapTrigonometricFunModHome_gr_471.gif]   as   [Graphics:../Images/MapTrigonometricFunModHome_gr_472.gif],    and    [Graphics:../Images/MapTrigonometricFunModHome_gr_473.gif]   as   [Graphics:../Images/MapTrigonometricFunModHome_gr_474.gif].

Then  
                     
                     [Graphics:../Images/MapTrigonometricFunModHome_gr_475.gif]   as   [Graphics:../Images/MapTrigonometricFunModHome_gr_476.gif].

                     [Graphics:../Images/MapTrigonometricFunModHome_gr_477.gif]   as   [Graphics:../Images/MapTrigonometricFunModHome_gr_478.gif].

                     [Graphics:../Images/MapTrigonometricFunModHome_gr_479.gif]   as   [Graphics:../Images/MapTrigonometricFunModHome_gr_480.gif].

                     [Graphics:../Images/MapTrigonometricFunModHome_gr_481.gif]   as   [Graphics:../Images/MapTrigonometricFunModHome_gr_482.gif].

                     [Graphics:../Images/MapTrigonometricFunModHome_gr_483.gif]   as   [Graphics:../Images/MapTrigonometricFunModHome_gr_484.gif].

                     [Graphics:../Images/MapTrigonometricFunModHome_gr_485.gif]   as   [Graphics:../Images/MapTrigonometricFunModHome_gr_486.gif].

We are done.   

If we are careful to observe that   [Graphics:../Images/MapTrigonometricFunModHome_gr_487.gif]  then we can consider the following limit argument.

                    [Graphics:../Images/MapTrigonometricFunModHome_gr_488.gif]  

We are really done.   

Aside.  We can look at a graph.

                    [Graphics:../Images/MapTrigonometricFunModHome_gr_489.gif]

                    The curve   [Graphics:../Images/MapTrigonometricFunModHome_gr_490.gif]   is asymptotic to the line   [Graphics:../Images/MapTrigonometricFunModHome_gr_491.gif].  

                    In quadrant III we have   [Graphics:../Images/MapTrigonometricFunModHome_gr_492.gif].

We are really really done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/MapTrigonometricFunModHome_gr_493.gif]

[Graphics:../Images/MapTrigonometricFunModHome_gr_494.gif]

In this case we use the two variable formula   [Graphics:../Images/MapTrigonometricFunModHome_gr_495.gif]  to get the correct answer.

[Graphics:../Images/MapTrigonometricFunModHome_gr_496.gif]

[Graphics:../Images/MapTrigonometricFunModHome_gr_497.gif]

You will get a wrong answer if you use the one variable formula   [Graphics:../Images/MapTrigonometricFunModHome_gr_498.gif].

[Graphics:../Images/MapTrigonometricFunModHome_gr_499.gif]

[Graphics:../Images/MapTrigonometricFunModHome_gr_500.gif]

The answer  [Graphics:../Images/MapTrigonometricFunModHome_gr_501.gif]  is wrong because the points  [Graphics:../Images/MapTrigonometricFunModHome_gr_502.gif]  lie in quadrant III when   [Graphics:../Images/MapTrigonometricFunModHome_gr_503.gif].

Indeed the curve  [Graphics:../Images/MapTrigonometricFunModHome_gr_504.gif]   is asymptotic to the line  [Graphics:../Images/MapTrigonometricFunModHome_gr_505.gif].

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell