Example 10.7. Find
the bilinear transformation
that maps the crescent-shaped region that lies inside the disk
and
outside the circle
onto
a horizontal strip.
Figure
10.7 The mapping
.
Explore Solution 10.7.
Enter three points and their images and solve for w =
S(z). For convenience we choose
which
are mapped onto the points
, respectively. In
this case we remove the terms involving
, in
the implicit formula, because this implies that
.
![[Graphics:../Images/MobiusTranformationMod_gr_230.gif]](../Images/MobiusTranformationMod_gr_230.gif)
Check our work and look at the images of
.
![]()
![]()
![]()
And we need to look at the images of three more
points;
and
.
![[Graphics:../Images/MobiusTranformationMod_gr_239.gif]](../Images/MobiusTranformationMod_gr_239.gif)
To illustrate the mapping, consider the inverse image of the horizontal strip. We will need to use the inverse function.
![[Graphics:../Images/MobiusTranformationMod_gr_241.gif]](../Images/MobiusTranformationMod_gr_241.gif)
Now plot the graphs using T[w] then the identity map.
![[Graphics:../Images/MobiusTranformationMod_gr_243.gif]](../Images/MobiusTranformationMod_gr_243.gif)
![]()
![[Graphics:../Images/MobiusTranformationMod_gr_245.gif]](../Images/MobiusTranformationMod_gr_245.gif)
![[Graphics:../Images/MobiusTranformationMod_gr_246.gif]](../Images/MobiusTranformationMod_gr_246.gif)
![]()
![]()
We have constructed the transformation
and
see that the image of the crescent-shaped region that lies inside the
disk
and
outside the circle
is
the horizontal strip
.