Solution 3.
Answer. The image
of
under
is
the unit disk
.
Solution. Method
I. The boundary of the right half
plane
is
the imaginary axis
,
and we can give the right half plane
a left orientation by using the points
.
The image points
, give
the unit circle
a
positive orientation and the disk
a
left orientation.
Therefore, the image of right half plane
under
is
.
Furthermore, as a double-check we can choose the
point
in
the right half plane
,
then
lies
in the unit disk
,
which leads us to conclude that the image region lies inside the unit
circle
.
We are done.
Solution. Method
II. In Example
10.3 we found the inverse transformation.
If we write
, then
we have
,
,
,
and
.
Using Equation (10-14), we find that the
inverse is given by
(10-16)
.
Then get
Then
implies
that
which
implies that
, which
in turn implies that
.
Therefore, the image of the right half plane
under
the mapping
is
the unit disk
.
We are really done.
Aside. We can let Mathematica double check our work.
We are really really done.
Aside. We can look
at some graphs of the mapping
.
![[Graphics:../Images/MobiusTranformationModHome_gr_117.gif]](../Images/MobiusTranformationModHome_gr_117.gif)
![[Graphics:../Images/MobiusTranformationModHome_gr_119.gif]](../Images/MobiusTranformationModHome_gr_119.gif)
The
image of the right half plane
under
is
the disk
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell