Solution 8.
Answer.
.
Solution. Method
I. Use the implicit
formula
.
Substitute the values given above and get
,
then simplify and obtain
.
Therefore,
.
We are done.
Aside. We can let Mathematica double check our work.
We are really done.
Solution. Method
II. The general form of a bilinear
transformation is
, and
it is not the case that both
.
So the desired formula must have one of the following two forms:
either
or
.
Let us assume that the first form
is
the one that works out.
Then we can set up three equations to solve
for
:
,
In the third equation we will take reciprocals and write it
as
, then
we have
,
then simplify these equations get
.
Use
to
rewrite the second equation as
then
solve the system of two equations
![]()
Subtracting the first equation from the second equation and
get
.
Use
in
the first equation and get
.
Substituting these into
produces
the desired result:
.
We are really really done.
Aside. We can let Mathematica double check our work.
We are really really really done.
Aside. We can look
at some graphs of the mapping
.
![[Graphics:../Images/MobiusTranformationModHome_gr_410.gif]](../Images/MobiusTranformationModHome_gr_410.gif)
![[Graphics:../Images/MobiusTranformationModHome_gr_412.gif]](../Images/MobiusTranformationModHome_gr_412.gif)
The
image of the upper half-plane
under
is
the upper half-plane
.
![[Graphics:../Images/MobiusTranformationModHome_gr_417.gif]](../Images/MobiusTranformationModHome_gr_417.gif)
![[Graphics:../Images/MobiusTranformationModHome_gr_419.gif]](../Images/MobiusTranformationModHome_gr_419.gif)
The
image of the right half-plane
under
is
the region
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell