Solution 9.
Answer.
.
Solution. Method
I. Use the implicit
formula
.
Substitute the values given above and get
Therefore,
.
We are done.
Aside. We can let Mathematica double check our work.
We are really done.
Solution. Method
II. The general form of a bilinear
transformation is
, and
it is not the case that both
.
So the desired formula must have one of the following two forms:
either
or
.
Let us assume that the first form
is
the one that works out.
Then we can set up three equations to solve
for
:
,
In the third equation we will take reciprocals and write it
as
, then
we have
,
then simplify these equations get
.
The first equation is easy to solve and we
get
.
Use
to
rewrite the second equation as
then
solve the system of two equations
Subtract the second equation from the first equation
obtain
and
get
.
Use
in
the second equation and get
.
Substituting these into
produces
the desired result:
.
We are really really done.
Aside. We can let Mathematica double check our work.
We are really really really done.
Aside. We can look
at some graphs of the mapping
.
![[Graphics:../Images/MobiusTranformationModHome_gr_467.gif]](../Images/MobiusTranformationModHome_gr_467.gif)
![[Graphics:../Images/MobiusTranformationModHome_gr_469.gif]](../Images/MobiusTranformationModHome_gr_469.gif)
The
image of the disk
under
is
the upper half-plane
.
![[Graphics:../Images/MobiusTranformationModHome_gr_474.gif]](../Images/MobiusTranformationModHome_gr_474.gif)
![[Graphics:../Images/MobiusTranformationModHome_gr_476.gif]](../Images/MobiusTranformationModHome_gr_476.gif)
The
image of the upper half-plane
under
is
the right half-plane
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell