Example 11.13.  Use Poisson's Integral formula to find the harmonic function [Graphics:Images/PoissonIntegralMod_gr_77.gif] that is harmonic in the upper half-plane [Graphics:Images/PoissonIntegralMod_gr_78.gif], that takes on the boundary values  

            [Graphics:Images/PoissonIntegralMod_gr_79.gif]  

Figure 11.15  The graph of [Graphics:Images/PoissonIntegralMod_gr_87.gif].

Explore Solution 11.13.

This is similar to Example 11.17, but the method of solution is different.

Using techniques from Section 11.2, the function  [Graphics:../Images/PoissonIntegralMod_gr_88.gif]  is harmonic in the upper half plane and takes on the boundary values
[Graphics:../Images/PoissonIntegralMod_gr_89.gif]

Thus, we should add it to the solution  [Graphics:../Images/PoissonIntegralMod_gr_90.gif]  in Example 11.12 to obtain the desired result.  However, with Mathematica  we need to use  [Graphics:../Images/PoissonIntegralMod_gr_91.gif].

Enter the function U[t] and use the Poisson integral to construct  [Graphics:../Images/PoissonIntegralMod_gr_92.gif].  

[Graphics:../Images/PoissonIntegralMod_gr_93.gif]



[Graphics:../Images/PoissonIntegralMod_gr_94.gif]

 

 

 

Use Mathematica to make a contour plot of the solution.

[Graphics:../Images/PoissonIntegralMod_gr_95.gif]





[Graphics:../Images/PoissonIntegralMod_gr_96.gif]

[Graphics:../Images/PoissonIntegralMod_gr_97.gif]

 

 

 

Then use Mathematica to make a 3D plot of the solution.

[Graphics:../Images/PoissonIntegralMod_gr_98.gif]





[Graphics:../Images/PoissonIntegralMod_gr_99.gif]

[Graphics:../Images/PoissonIntegralMod_gr_100.gif]

Therefore, the function
[Graphics:../Images/PoissonIntegralMod_gr_101.gif]  
is harmonic in the upper half-plane  [Graphics:../Images/PoissonIntegralMod_gr_102.gif],  and takes on the desired boundary values.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2006 John H. Mathews, Russell W. Howell