Exercise 9.  Use residues to find the partial fraction representations of  

9 (a).  [Graphics:Images/ResidueCalcModHome_gr_1072.gif].

Solution 9 (a).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/ResidueCalcModHome_gr_1073.gif].  

Solution.   Factoring the denominator, we obtain

                    [Graphics:../Images/ResidueCalcModHome_gr_1074.gif]  

The roots are  [Graphics:../Images/ResidueCalcModHome_gr_1075.gif].  

Applying the method outlined in  Example 8.7 yields  

                    [Graphics:../Images/ResidueCalcModHome_gr_1076.gif]  

Computing the residues using Theorem 8.2 we obtain:

                    [Graphics:../Images/ResidueCalcModHome_gr_1077.gif]

                    
                    
                    [Graphics:../Images/ResidueCalcModHome_gr_1078.gif]

We are done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/ResidueCalcModHome_gr_1079.gif]

[Graphics:../Images/ResidueCalcModHome_gr_1080.gif]


[Graphics:../Images/ResidueCalcModHome_gr_1081.gif]

[Graphics:../Images/ResidueCalcModHome_gr_1082.gif]


[Graphics:../Images/ResidueCalcModHome_gr_1083.gif]

[Graphics:../Images/ResidueCalcModHome_gr_1084.gif]

Maple can check our work too!

     > residue( 1/(z^2+3*z+2), z=-1 );

               1

     > residue( 1/(z^2+3*z+2), z=-2 );

               -1

We are really done.   

Aside.  We can use Mathematica built in command "Apart."

[Graphics:../Images/ResidueCalcModHome_gr_1085.gif]

[Graphics:../Images/ResidueCalcModHome_gr_1086.gif]

Or we can use Maple's built in command "convert."

     > convert( 1/(z^2+3*z+2), parfrac, z);

               
[Graphics:../Images/ResidueCalcModHome_gr_1087.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell