Exercise 9. Use residues to find the partial fraction representations of
9 (a).
.
Solution 9 (a).
See text and/or instructor's solution manual.
Answer.
.
Solution. Factoring
the denominator, we obtain
The roots are
.
Applying the method outlined in Example
8.7 yields
Computing the residues using Theorem
8.2 we obtain:
![[Graphics:../Images/ResidueCalcModHome_gr_1077.gif]](../Images/ResidueCalcModHome_gr_1077.gif)
![[Graphics:../Images/ResidueCalcModHome_gr_1078.gif]](../Images/ResidueCalcModHome_gr_1078.gif)
We are done.
Aside. We can let Mathematica double check our work.
Maple can check our work too!
>
residue( 1/(z^2+3*z+2), z=-1 );
1
>
residue( 1/(z^2+3*z+2), z=-2 );
-1
We are really done.
Aside. We can use Mathematica built in command "Apart."
Or we can use Maple's built in command "convert."
>
convert( 1/(z^2+3*z+2), parfrac, z);
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell