Exercise 11.  Let [Graphics:Images/ResidueCalcModHome_gr_1213.gif]  be analytic at the points  [Graphics:Images/ResidueCalcModHome_gr_1214.gif].  

If   [Graphics:Images/ResidueCalcModHome_gr_1215.gif],   then show that   [Graphics:Images/ResidueCalcModHome_gr_1216.gif]   for  [Graphics:Images/ResidueCalcModHome_gr_1217.gif].  

Hint:  The solution is a little tricky.  You might need to use  [Graphics:Images/ResidueCalcModHome_gr_1218.gif].  

Solution 11.

See text and/or instructor's solution manual.

Solution.   By Theorem 8.2 we have  [Graphics:../Images/ResidueCalcModHome_gr_1219.gif],  where n is any integer.  

Since  [Graphics:../Images/ResidueCalcModHome_gr_1220.gif],  and because  [Graphics:../Images/ResidueCalcModHome_gr_1221.gif]  is analytic at n,  we use L'Hôpital's rule to get  [Graphics:../Images/ResidueCalcModHome_gr_1222.gif].  

Explain how this gives the result.

        [Graphics:../Images/ResidueCalcModHome_gr_1223.gif]  

Caveat:  [Graphics:../Images/ResidueCalcModHome_gr_1224.gif].   Unfortunately, Mathematica is in error and computes this limit to be zero.  

The computation using L'Hôpital's rule will give the correct answer  [Graphics:../Images/ResidueCalcModHome_gr_1225.gif].

[Graphics:../Images/ResidueCalcModHome_gr_1226.gif]

[Graphics:../Images/ResidueCalcModHome_gr_1227.gif]


[Graphics:../Images/ResidueCalcModHome_gr_1228.gif]

[Graphics:../Images/ResidueCalcModHome_gr_1229.gif]


[Graphics:../Images/ResidueCalcModHome_gr_1230.gif]

[Graphics:../Images/ResidueCalcModHome_gr_1231.gif]

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 



This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell