Exercise
1. Find
for
the following functions:
1
(g).
.
Solution 1 (g).
See text and/or instructor's solution manual.
Answer. ![]()
Solution. Use
the fact that
and
express this function in the following form
The function
has
a removable singularity at
.
Here we have ![]()
and
according to Definition
8.1
the residue is seen to be
.
We are done.
Aside. We can let Mathematica double check our work.
Maple can check our work too!
>
series( sin(z)/z, z=0,12 );
We are really really done.
Aside. Both
and
are capable of finding residues.
>
residue( sin(z)/z, z=0 );
0
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell