Exercise
7. Let
.
7 (a). Show
that there are no zeros in
.
Solution 7 (a).
Solution. Let
. Then
for
we
have
Since
has
no roots in
, neither
does
, by
Remark 8.5 to Rouché's
Theorem.
We are done.
Aside. We can use Mathematica to verify the inequality mentioned above.
![[Graphics:../Images/RoucheTheoremModHome_gr_476.gif]](../Images/RoucheTheoremModHome_gr_476.gif)
For
on
the circle
we
have the inequality
![]()
We are really done.
Aside. We can use Mathematica to plot the zeros of g(z).
![[Graphics:../Images/RoucheTheoremModHome_gr_480.gif]](../Images/RoucheTheoremModHome_gr_480.gif)
There
are no zeros of
that
lie in the disk
.
Aside. We can let
Mathematica double check our work.
However, the zeros of
have
a complicated algebraic representation.
So we might prefer numerical approximations:
![[Graphics:../Images/RoucheTheoremModHome_gr_484.gif]](../Images/RoucheTheoremModHome_gr_484.gif)
![[Graphics:../Images/RoucheTheoremModHome_gr_486.gif]](../Images/RoucheTheoremModHome_gr_486.gif)
The moduli of these roots are:
Remark. A
factorization of the polynomial using numerical approximations for
the coefficients is
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell