Exercise
3. Let
.
3 (a). Show
that there are no zeros in
.
Solution 3 (a).
See text and/or instructor's solution manual.
Solution. Let
. Then
for
we
have
Since
has
no roots in
, neither
does
, by
Remark 8.5 to Rouché's
Theorem.
We are done.
Aside. We can use Mathematica to verify the inequality mentioned above.
![[Graphics:../Images/RoucheTheoremModHome_gr_287.gif]](../Images/RoucheTheoremModHome_gr_287.gif)
For
on
the circle
we
have the inequality
![]()
We are really done.
Aside. We can use Mathematica to plot the zeros of g(z).
![[Graphics:../Images/RoucheTheoremModHome_gr_291.gif]](../Images/RoucheTheoremModHome_gr_291.gif)
There
are no zeros of
in
.
Aside. We can let
Mathematica double check our work.
However, the zeros of
do
not have a nice algebraic solution.
So we must settle for numerical approximations:
![[Graphics:../Images/RoucheTheoremModHome_gr_295.gif]](../Images/RoucheTheoremModHome_gr_295.gif)
![[Graphics:../Images/RoucheTheoremModHome_gr_296.gif]](../Images/RoucheTheoremModHome_gr_296.gif)
The moduli of these roots are:
Remark. A
factorization of the polynomial using numerical approximations for
the coefficients is
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell