Exercise 11.  Show that   [Graphics:Images/SchwarzChristoffelModHome_gr_536.gif]   maps the upper half-plane   [Graphics:Images/SchwarzChristoffelModHome_gr_537.gif]   

onto the domain indicated in Figure 11.85.                     Figure 11.85.

Hint.  Set  [Graphics:Images/SchwarzChristoffelModHome_gr_538.gif],  [Graphics:Images/SchwarzChristoffelModHome_gr_539.gif],  and  [Graphics:Images/SchwarzChristoffelModHome_gr_540.gif],  [Graphics:Images/SchwarzChristoffelModHome_gr_541.gif],  respectively, and let   [Graphics:Images/SchwarzChristoffelModHome_gr_542.gif].    

Solution 11.

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/SchwarzChristoffelModHome_gr_543.gif],   integrate and get   [Graphics:../Images/SchwarzChristoffelModHome_gr_544.gif],  

then use the conditions   [Graphics:../Images/SchwarzChristoffelModHome_gr_545.gif]   and obtain   [Graphics:../Images/SchwarzChristoffelModHome_gr_546.gif].

Answer.    [Graphics:../Images/SchwarzChristoffelModHome_gr_547.gif],  integrate and get  [Graphics:../Images/SchwarzChristoffelModHome_gr_548.gif].

Solution.   Along the x-axis use the points   [Graphics:../Images/SchwarzChristoffelModHome_gr_549.gif].   The exterior angles are  [Graphics:../Images/SchwarzChristoffelModHome_gr_550.gif],  

and the formula for the derivative [Graphics:../Images/SchwarzChristoffelModHome_gr_551.gif] is  given by the Schwarz-Christoffel formula  

The exterior angles are  [Graphics:../Images/SchwarzChristoffelModHome_gr_552.gif],  and the formula for the derivative [Graphics:../Images/SchwarzChristoffelModHome_gr_553.gif] is  

                    [Graphics:../Images/SchwarzChristoffelModHome_gr_554.gif]

Integrate and get  

                    [Graphics:../Images/SchwarzChristoffelModHome_gr_555.gif]

        The images of   [Graphics:../Images/SchwarzChristoffelModHome_gr_556.gif],   are   [Graphics:../Images/SchwarzChristoffelModHome_gr_557.gif],   respectively.

Use   [Graphics:../Images/SchwarzChristoffelModHome_gr_558.gif],   and obtain the system of equations

                    [Graphics:../Images/SchwarzChristoffelModHome_gr_559.gif]  

Which simplifies to be   

                    [Graphics:../Images/SchwarzChristoffelModHome_gr_560.gif]  

The values  [Graphics:../Images/SchwarzChristoffelModHome_gr_561.gif]  are solutions for this system of equations.

Therefore,   

                    [Graphics:../Images/SchwarzChristoffelModHome_gr_562.gif].

 

We are done.   

 

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/SchwarzChristoffelModHome_gr_563.gif]

[Graphics:../Images/SchwarzChristoffelModHome_gr_564.gif]


[Graphics:../Images/SchwarzChristoffelModHome_gr_565.gif]

[Graphics:../Images/SchwarzChristoffelModHome_gr_566.gif]


[Graphics:../Images/SchwarzChristoffelModHome_gr_567.gif]

[Graphics:../Images/SchwarzChristoffelModHome_gr_568.gif]


We are really done.   

 

        We can let Mathematica graph some of the streamlines.

 



                    [Graphics:../Images/SchwarzChristoffelModHome_gr_570.gif]          [Graphics:../Images/SchwarzChristoffelModHome_gr_571.gif]

  

                    The streamlines in the w-plane for the mapping   [Graphics:../Images/SchwarzChristoffelModHome_gr_572.gif].   

 

We are really really done.   

 

Aside.  For illustration purposes we can graph the mapping   [Graphics:../Images/SchwarzChristoffelModHome_gr_573.gif].  



                    [Graphics:../Images/SchwarzChristoffelModHome_gr_575.gif]          [Graphics:../Images/SchwarzChristoffelModHome_gr_576.gif]

  

                    The mapping   [Graphics:../Images/SchwarzChristoffelModHome_gr_577.gif].    

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell