Solution 3 (a).
See text and/or instructor's solution manual.
Answer.
has
a simple pole at the origin.
Solution. Use
a convenient method to determine where the denominator is
zero.
For example, use the series
and
get
Then
Now apply Corollary
7.5 to conclude that
has
a simple pole at the origin.
You do not need to find any other singularity for this exercise.
We are done.
Aside. We can let Mathematica double check our work.
We are really done.
![[Graphics:../Images/SingularityZeroPoleModHome_gr_912.gif]](../Images/SingularityZeroPoleModHome_gr_912.gif)
The simple pole at the origin.
![[Graphics:../Images/SingularityZeroPoleModHome_gr_913.gif]](../Images/SingularityZeroPoleModHome_gr_913.gif)
A
plot for
.
Remark. There does
not seem to be an analytic way to determine the other poles
of
.
For this exercise it will suffice to determine that there is a simple
pole at the origin.
However, the graphs below indicated that there are infinitely many
poles.
![[Graphics:../Images/SingularityZeroPoleModHome_gr_916.gif]](../Images/SingularityZeroPoleModHome_gr_916.gif)
![[Graphics:../Images/SingularityZeroPoleModHome_gr_917.gif]](../Images/SingularityZeroPoleModHome_gr_917.gif)
A
plot for
.
Remark. There does
not seem to be an analytic way to determine solutions
to
.
However, the graph below indicated that there are
solutions.
It is possible to determine the location of other non-zero solutions,
but it requires a numerical analysis computation.
![[Graphics:../Images/SingularityZeroPoleModHome_gr_920.gif]](../Images/SingularityZeroPoleModHome_gr_920.gif)
A
plot for
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell