Solution 3 (c).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/SingularityZeroPoleModHome_gr_940.gif]  has an essential singularity at the origin.  

Solution.   Use the fact that  [Graphics:../Images/SingularityZeroPoleModHome_gr_941.gif],  and express this function as a Laurent series.  

Use the substitution  [Graphics:../Images/SingularityZeroPoleModHome_gr_942.gif]  and get  

                    [Graphics:../Images/SingularityZeroPoleModHome_gr_943.gif]  

Then apply  Definition 7.5 to conclude that [Graphics:../Images/SingularityZeroPoleModHome_gr_944.gif]  has an essential singularity at the origin.

We are  done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/SingularityZeroPoleModHome_gr_945.gif]

[Graphics:../Images/SingularityZeroPoleModHome_gr_946.gif]


[Graphics:../Images/SingularityZeroPoleModHome_gr_947.gif]

[Graphics:../Images/SingularityZeroPoleModHome_gr_948.gif]


[Graphics:../Images/SingularityZeroPoleModHome_gr_949.gif]

[Graphics:../Images/SingularityZeroPoleModHome_gr_950.gif]

We are really done.   

                    [Graphics:../Images/SingularityZeroPoleModHome_gr_951.gif]

                              The essential singularity at the origin.

                    [Graphics:../Images/SingularityZeroPoleModHome_gr_952.gif][Graphics:../Images/SingularityZeroPoleModHome_gr_954.gif]

                              A plot for   [Graphics:../Images/SingularityZeroPoleModHome_gr_953.gif].                  A plot for   [Graphics:../Images/SingularityZeroPoleModHome_gr_955.gif].  

                              Note. These are plots of the real and imaginary parts of the function.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell