Solution 3 (g).

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/SingularityZeroPoleModHome_gr_1020.gif]   has a removable singularity at the origin if we define  [Graphics:../Images/SingularityZeroPoleModHome_gr_1021.gif].

Solution.   Consider  [Graphics:../Images/SingularityZeroPoleModHome_gr_1022.gif].  Use the known series  [Graphics:../Images/SingularityZeroPoleModHome_gr_1023.gif]  and write

                    [Graphics:../Images/SingularityZeroPoleModHome_gr_1024.gif].

Substitute this series in the numerator and obtain

                    [Graphics:../Images/SingularityZeroPoleModHome_gr_1025.gif]   

Then apply  Definition 7.5 to conclude that  [Graphics:../Images/SingularityZeroPoleModHome_gr_1026.gif]   has a removable singularity at the origin.

We are  done.   

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/SingularityZeroPoleModHome_gr_1027.gif]

[Graphics:../Images/SingularityZeroPoleModHome_gr_1028.gif]


[Graphics:../Images/SingularityZeroPoleModHome_gr_1029.gif]

[Graphics:../Images/SingularityZeroPoleModHome_gr_1030.gif]


[Graphics:../Images/SingularityZeroPoleModHome_gr_1031.gif]

[Graphics:../Images/SingularityZeroPoleModHome_gr_1032.gif]

We are really done.   

                    [Graphics:../Images/SingularityZeroPoleModHome_gr_1033.gif]

                              The removable singularity at the origin.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell