Example
11.30. (Source and
sink of equal strength) Let a source and sink
of unit strength be located at the points
and
,
respectively. The complex potential for a fluid flowing
from the source at
to
the sink at
is
.
![]()
![]()
Figure 11.95 (a) Source and sink of unit strength.
Explore Solution 11.30.
Enter the formula for the complex potential F[z].
![[Graphics:../Images/SourceSinkMod_gr_61.gif]](../Images/SourceSinkMod_gr_61.gif)
Use Mathematica to make a density plot of the velocity potential.
![[Graphics:../Images/SourceSinkMod_gr_63.gif]](../Images/SourceSinkMod_gr_63.gif)
![[Graphics:../Images/SourceSinkMod_gr_64.gif]](../Images/SourceSinkMod_gr_64.gif)
Use Mathematica to make a contour plot of the stream function.
![[Graphics:../Images/SourceSinkMod_gr_66.gif]](../Images/SourceSinkMod_gr_66.gif)
![[Graphics:../Images/SourceSinkMod_gr_67.gif]](../Images/SourceSinkMod_gr_67.gif)
Use Mathematica to make a contour plot of the velocity potential.
![[Graphics:../Images/SourceSinkMod_gr_69.gif]](../Images/SourceSinkMod_gr_69.gif)
![[Graphics:../Images/SourceSinkMod_gr_70.gif]](../Images/SourceSinkMod_gr_70.gif)
Find the inverse of the function F[Z].
![[Graphics:../Images/SourceSinkMod_gr_72.gif]](../Images/SourceSinkMod_gr_72.gif)
Use Mathematica to graph the stream functions using f[x,y].
![[Graphics:../Images/SourceSinkMod_gr_74.gif]](../Images/SourceSinkMod_gr_74.gif)
![[Graphics:../Images/SourceSinkMod_gr_75.gif]](../Images/SourceSinkMod_gr_75.gif)
The stream function for a fluid flowing from the source at z = +1 to the sink at z = -1.
![[Graphics:../Images/SourceSinkMod_gr_77.gif]](../Images/SourceSinkMod_gr_77.gif)
![[Graphics:../Images/SourceSinkMod_gr_78.gif]](../Images/SourceSinkMod_gr_78.gif)
The velocity potential for a fluid flowing from the source at z = +1 to the sink at z = -1.
![[Graphics:../Images/SourceSinkMod_gr_80.gif]](../Images/SourceSinkMod_gr_80.gif)
The streamlines and velocity potential for a fluid flowing from the source at z = +1 to the sink at z = -1.