Extra Example
2. Use a Schwarz-Christoffel transformation to
show that the conformal mapping
![]()
will map the flow in the upper half-plane from a source
at
onto
the flow from a channel with
into
a sector, as shown in Figure 11.106.
Hint: Set
and
. Use
the change of variable
in
the resulting integral.
![]()
![]()
Figure 11.106 Flow from a channel into a sector in the first quadrant.
Explore Extra Solution 2.
![[Graphics:../Images/SourceSinkMod_gr_280.gif]](../Images/SourceSinkMod_gr_280.gif)
Use Mathematica to graph conformal mapping w = S(z).
![[Graphics:../Images/SourceSinkMod_gr_282.gif]](../Images/SourceSinkMod_gr_282.gif)
![[Graphics:../Images/SourceSinkMod_gr_283.gif]](../Images/SourceSinkMod_gr_283.gif)
![[Graphics:../Images/SourceSinkMod_gr_285.gif]](../Images/SourceSinkMod_gr_285.gif)
![[Graphics:../Images/SourceSinkMod_gr_286.gif]](../Images/SourceSinkMod_gr_286.gif)
We are done.
Aside. We can extend
the flow into the fourth quadrant using symmetry.
![[Graphics:../Images/SourceSinkMod_gr_288.gif]](../Images/SourceSinkMod_gr_288.gif)
![[Graphics:../Images/SourceSinkMod_gr_290.gif]](../Images/SourceSinkMod_gr_290.gif)
![[Graphics:../Images/SourceSinkMod_gr_291.gif]](../Images/SourceSinkMod_gr_291.gif)