Exercise 11.   Consider the complex potential   [Graphics:Images/SourceSinkModHome_gr_627.gif]   given implicitly by   [Graphics:Images/SourceSinkModHome_gr_628.gif].

11 (a).   Show that  [Graphics:Images/SourceSinkModHome_gr_629.gif]  determines the ideal fluid flow through an open channel bounded by the rays  

        [Graphics:Images/SourceSinkModHome_gr_630.gif],    and    [Graphics:Images/SourceSinkModHome_gr_631.gif].  

as indicated in Figure 11.109.                     Figure 11.109.

11 (b).   Show that the streamline  [Graphics:Images/SourceSinkModHome_gr_632.gif]  of the flow is given by the parametric equations  

    [Graphics:Images/SourceSinkModHome_gr_633.gif]   and   [Graphics:Images/SourceSinkModHome_gr_634.gif],    for    [Graphics:Images/SourceSinkModHome_gr_635.gif].

Solution 11.

See text and/or instructor's solution manual.

Answer.   

Solution.   Use the result of Exercise 7 in Section 11.9.  

We showed that   [Graphics:../Images/SourceSinkModHome_gr_636.gif]   maps the upper half-plane   [Graphics:../Images/SourceSinkModHome_gr_637.gif]   onto

the upper half-plane   [Graphics:../Images/SourceSinkModHome_gr_638.gif]   slit along the ray   [Graphics:../Images/SourceSinkModHome_gr_639.gif],   as shown in Figure 11.81.  

Observe that this function will also map a flow across the entire z-plane  (minus the x-axis) onto the region show in Figure 11.109.

Set  [Graphics:../Images/SourceSinkModHome_gr_640.gif],  [Graphics:../Images/SourceSinkModHome_gr_641.gif],  and  [Graphics:../Images/SourceSinkModHome_gr_642.gif],  [Graphics:../Images/SourceSinkModHome_gr_643.gif],  respectively, and let  [Graphics:../Images/SourceSinkModHome_gr_644.gif].    

The exterior angles are  [Graphics:../Images/SourceSinkModHome_gr_645.gif],  and the formula for the derivative  [Graphics:../Images/SourceSinkModHome_gr_646.gif]  is  

            [Graphics:../Images/SourceSinkModHome_gr_647.gif]   
Integrate and get

            [Graphics:../Images/SourceSinkModHome_gr_648.gif]

            [Graphics:../Images/SourceSinkModHome_gr_649.gif]

            [Graphics:../Images/SourceSinkModHome_gr_650.gif]
            

The graph for the streamlines can be produced by using the formula   [Graphics:../Images/SourceSinkModHome_gr_651.gif]   and making the substitution  [Graphics:../Images/SourceSinkModHome_gr_652.gif]  for  [Graphics:../Images/SourceSinkModHome_gr_653.gif].  

Hence, we obtain   [Graphics:../Images/SourceSinkModHome_gr_654.gif].  

Then the image of the line   [Graphics:../Images/SourceSinkModHome_gr_655.gif]   will be  

                    [Graphics:../Images/SourceSinkModHome_gr_656.gif]  

Thus the parametric equations for the streamlines will be  

                    [Graphics:../Images/SourceSinkModHome_gr_657.gif],   and  

                    [Graphics:../Images/SourceSinkModHome_gr_658.gif],   for  [Graphics:../Images/SourceSinkModHome_gr_659.gif].  

 

We are really done.   

 

        We can let Mathematica draw a graph of the streamlines.

 

                    [Graphics:../Images/SourceSinkModHome_gr_660.gif]

                    The streamlines  [Graphics:../Images/SourceSinkModHome_gr_661.gif].  

 

We are really really done.   

 

        We can use Mathematica to graph the conformal mapping   [Graphics:../Images/SourceSinkModHome_gr_662.gif].  

 

           [Graphics:../Images/SourceSinkModHome_gr_663.gif]          [Graphics:../Images/SourceSinkModHome_gr_664.gif]

                      The conformal mapping   [Graphics:../Images/SourceSinkModHome_gr_665.gif].  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell