Exercise
7. Use a Schwarz-Christoffel
transformation to find a conformal
mapping
that
will map the flow
in the upper half-plane onto the flow from a channel into a
quadrant,
as indicated in Figure
11.105.
Figure 11.105.
Solution 7.
See text and/or instructor's solution manual.
Answer. Use
a
, for
convenience, set
, and
.
Integrate and get
,
which will map the flow in the upper half-plane from a source
at
onto
the flow from a channel with
into
the first quadrant, as shown in Figure
11.105.
Solution. The
details are given in the solution of Exercise 8 in Section
11.9.
Along the x-axis use the
points
. The
exterior angles are
,
and the formula for the derivative
is given by the Schwarz-Christoffel
formula
For convenience, set
,
.
Integrate and get
.
The first integral is easy to get
.
The second integral can be found using the suggested change of
variable
Make substitutions in the integral
Now use the substitution
and
get
.
Now combine this with the first integral and
obtain
![[Graphics:../Images/SourceSinkModHome_gr_420.gif]](../Images/SourceSinkModHome_gr_420.gif)
Therefore,
.
We are done.
Aside. We can let Mathematica double check our work.
We are really done.
We are really really done.
We can let Mathematica graph some of the streamlines.
![[Graphics:../Images/SourceSinkModHome_gr_430.gif]](../Images/SourceSinkModHome_gr_430.gif)
The
flow from a channel
into
the first quadrant.
We are really really really done.
Aside. We can extend the flow into the third and fourth quadrants using symmetry.
![[Graphics:../Images/SourceSinkModHome_gr_432.gif]](../Images/SourceSinkModHome_gr_432.gif)
The
flow from a channel
into
the right half-plane.
We are really really really really done.
We can use Mathematica to check our work and graph the
conformal mapping
.
![[Graphics:../Images/SourceSinkModHome_gr_436.gif]](../Images/SourceSinkModHome_gr_436.gif)
The
conformal mapping
.
Aside. We can extend the flow into the third and fourth quadrants using symmetry.
![[Graphics:../Images/SourceSinkModHome_gr_439.gif]](../Images/SourceSinkModHome_gr_439.gif)
The
conformal mapping
.
We are really really really really really done.
There are other
possible formulas for the solution. The logarithm term
could also be written in the form
.
Aside. We can let Mathematica double check our work.
And if the inverse hyperbolic functions are used then this can be
written as
.
Observe that the
conditions
and
, are
met.
The images of
, are
, respectively.
![[Graphics:../Images/SourceSinkModHome_gr_455.gif]](../Images/SourceSinkModHome_gr_455.gif)
From calculus we have
so
we will use
and
write
![[Graphics:../Images/SourceSinkModHome_gr_458.gif]](../Images/SourceSinkModHome_gr_458.gif)
Remark 1. If
the computer algebra Mathematica is used to perform the
integration then the answer is
.
Remark
2. If the computer algebra Maple is
used to perform the integration then the answer is
.
Or if the second integral is treated separately, then Maple's answer
will be
.
Summary of Formulas. The following five mapping of the upper half-plane will produce the same results.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell