Exercise 8.   Use a Schwarz-Christoffel transformation to find a conformal mapping  [Graphics:Images/SourceSinkModHome_gr_463.gif]  that will map the flow

in the upper half-plane onto the flow from a channel into a sector,

as indicated in Figure 11.106.                     Figure 11.106.

Solution 8.

See text and/or instructor's solution manual.

Answer.   [Graphics:../Images/SourceSinkModHome_gr_464.gif],   for convenience set  [Graphics:../Images/SourceSinkModHome_gr_465.gif].   

Integrate and get   [Graphics:../Images/SourceSinkModHome_gr_466.gif],    

which will map the flow in the upper half-plane from a source at  [Graphics:../Images/SourceSinkModHome_gr_467.gif]  onto the flow from a channel with  [Graphics:../Images/SourceSinkModHome_gr_468.gif]  into a sector, as shown in Figure 11.106.

 

Hint:  Set  [Graphics:../Images/SourceSinkModHome_gr_469.gif] and [Graphics:../Images/SourceSinkModHome_gr_470.gif].  Use the change of variable  [Graphics:../Images/SourceSinkModHome_gr_471.gif]  in the resulting integral.

Solution.   Along the x-axis use the points   [Graphics:../Images/SourceSinkModHome_gr_472.gif].   The exterior angles are  [Graphics:../Images/SourceSinkModHome_gr_473.gif],  

and the formula for the derivative [Graphics:../Images/SourceSinkModHome_gr_474.gif] is  given by the Schwarz-Christoffel formula  

                    [Graphics:../Images/SourceSinkModHome_gr_475.gif]   

For convenience set  [Graphics:../Images/SourceSinkModHome_gr_476.gif].   

Now integrate and get    

                    [Graphics:../Images/SourceSinkModHome_gr_477.gif].  

The first integral is easy to get

                    [Graphics:../Images/SourceSinkModHome_gr_478.gif].  
            

The second integral can be found using the change of variable

                    [Graphics:../Images/SourceSinkModHome_gr_479.gif]  
            
make these substitutions in the integral and get

                    [Graphics:../Images/SourceSinkModHome_gr_480.gif]  

Next use the substitution   [Graphics:../Images/SourceSinkModHome_gr_481.gif]   and get

                    [Graphics:../Images/SourceSinkModHome_gr_482.gif]

Now combine this with the first integral and get

                    [Graphics:../Images/SourceSinkModHome_gr_483.gif]
                    
Therefore,  

                    [Graphics:../Images/SourceSinkModHome_gr_484.gif].

 

We are done.   

 

Aside.  We can let Mathematica double check our work.

[Graphics:../Images/SourceSinkModHome_gr_485.gif]

[Graphics:../Images/SourceSinkModHome_gr_486.gif]


[Graphics:../Images/SourceSinkModHome_gr_487.gif]

[Graphics:../Images/SourceSinkModHome_gr_488.gif]

Use the identity  [Graphics:../Images/SourceSinkModHome_gr_489.gif]  and write the solution using logarithms

Therefore,  

                    [Graphics:../Images/SourceSinkModHome_gr_490.gif].  

 

We are really done.   

 

Aside.  We can let Mathematica double check our work.

 

[Graphics:../Images/SourceSinkModHome_gr_491.gif]


[Graphics:../Images/SourceSinkModHome_gr_492.gif]

[Graphics:../Images/SourceSinkModHome_gr_493.gif]

[Graphics:../Images/SourceSinkModHome_gr_494.gif]


We are really really done.   

 

        We can let Mathematica graph some of the streamlines.

 

                    [Graphics:../Images/SourceSinkModHome_gr_495.gif]

                      The flow from a channel  [Graphics:../Images/SourceSinkModHome_gr_496.gif]  into a into a sector.

 

We are really really really done.   

 

Aside.  We can extend the flow into the third and fourth quadrants using symmetry.

 

                    [Graphics:../Images/SourceSinkModHome_gr_497.gif]

                    The flow from a channel  [Graphics:../Images/SourceSinkModHome_gr_498.gif]  into a into a sector.

 

We are really really really really done.   

 

          We can use Mathematica to graph the conformal mapping   [Graphics:../Images/SourceSinkModHome_gr_499.gif].

 

          [Graphics:../Images/SourceSinkModHome_gr_500.gif]          [Graphics:../Images/SourceSinkModHome_gr_501.gif]

                              The conformal mapping   [Graphics:../Images/SourceSinkModHome_gr_502.gif].   

 

Aside.  We can extend the flow into the third and fourth quadrants using symmetry.

 

          [Graphics:../Images/SourceSinkModHome_gr_503.gif]          [Graphics:../Images/SourceSinkModHome_gr_504.gif]

                                The conformal mapping   [Graphics:../Images/SourceSinkModHome_gr_505.gif].   

 

We are really really really really really done.   

 

        Observe that the conditions   [Graphics:../Images/SourceSinkModHome_gr_506.gif]  and  [Graphics:../Images/SourceSinkModHome_gr_507.gif],   are met.

The images of   [Graphics:../Images/SourceSinkModHome_gr_508.gif],   are   [Graphics:../Images/SourceSinkModHome_gr_509.gif],   respectively.

                    [Graphics:../Images/SourceSinkModHome_gr_510.gif]


                    [Graphics:../Images/SourceSinkModHome_gr_511.gif]
                    
                    
From calculus we have   [Graphics:../Images/SourceSinkModHome_gr_512.gif]   so we will use   [Graphics:../Images/SourceSinkModHome_gr_513.gif]   and write

                    [Graphics:../Images/SourceSinkModHome_gr_514.gif].

 

Remark 1.1   If the computer algebra  Mathematica is used to perform the integration then the answer is

                    [Graphics:../Images/SourceSinkModHome_gr_515.gif]  

which gives the correct result but uses the a specialized hypergeometric function.

[Graphics:../Images/SourceSinkModHome_gr_516.gif]
[Graphics:../Images/SourceSinkModHome_gr_517.gif]

Remark 1.2   Mathematica 7 will get the following formula for the integral

            [Graphics:../Images/SourceSinkModHome_gr_518.gif]

            [Graphics:../Images/SourceSinkModHome_gr_519.gif]

[Graphics:../Images/SourceSinkModHome_gr_520.gif]
[Graphics:../Images/SourceSinkModHome_gr_521.gif]

Remark 2.   If the computer algebra Maple is used to perform the integration then the answer is

                    [Graphics:../Images/SourceSinkModHome_gr_522.gif].  

 

Summary of Formulas.   The following four mapping of the upper half-plane will produce the same results.


                    [Graphics:../Images/SourceSinkModHome_gr_523.gif]  

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

This solution is complements of the authors.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(c) 2008 John H. Mathews, Russell W. Howell