Exercise
8. Use a Schwarz-Christoffel
transformation to find a conformal mapping
that
will map the flow
in the upper half-plane onto the flow from a channel into a
sector,
as indicated in Figure
11.106.
Figure 11.106.
Solution 8.
See text and/or instructor's solution manual.
Answer.
, for
convenience set
.
Integrate and get
,
which will map the flow in the upper half-plane from a source
at
onto
the flow from a channel with
into
a sector, as shown in Figure
11.106.
Hint: Set
and
. Use
the change of variable
in
the resulting integral.
Solution. Along
the x-axis use the points
. The
exterior angles are
,
and the formula for the derivative
is given by the Schwarz-Christoffel
formula
For convenience set
.
Now integrate and get
.
The first integral is easy to get
.
The second integral can be found using the change of variable
make these substitutions in the integral and get
Next use the substitution
and
get
![]()
Now combine this with the first integral and get
![[Graphics:../Images/SourceSinkModHome_gr_483.gif]](../Images/SourceSinkModHome_gr_483.gif)
Therefore,
.
We are done.
Aside. We can let Mathematica double check our work.
Use the identity
and
write the solution using logarithms
Therefore,
.
We are really done.
Aside. We can let Mathematica double check our work.
We are really really done.
We can let Mathematica graph some of the streamlines.
![[Graphics:../Images/SourceSinkModHome_gr_495.gif]](../Images/SourceSinkModHome_gr_495.gif)
The
flow from a channel
into
a into a sector.
We are really really really done.
Aside. We can extend the flow into the third and fourth quadrants using symmetry.
![[Graphics:../Images/SourceSinkModHome_gr_497.gif]](../Images/SourceSinkModHome_gr_497.gif)
The
flow from a channel
into
a into a sector.
We are really really really really done.
We can
use Mathematica to graph the conformal
mapping
.
![[Graphics:../Images/SourceSinkModHome_gr_501.gif]](../Images/SourceSinkModHome_gr_501.gif)
The
conformal mapping
.
Aside. We can extend the flow into the third and fourth quadrants using symmetry.
![[Graphics:../Images/SourceSinkModHome_gr_504.gif]](../Images/SourceSinkModHome_gr_504.gif)
The
conformal mapping
.
We are really really really really really done.
Observe that the
conditions
and
, are
met.
The images of
, are
, respectively.
![[Graphics:../Images/SourceSinkModHome_gr_510.gif]](../Images/SourceSinkModHome_gr_510.gif)
![[Graphics:../Images/SourceSinkModHome_gr_511.gif]](../Images/SourceSinkModHome_gr_511.gif)
From calculus we have
so
we will use
and
write
.
Remark 1.1 If
the computer algebra Mathematica is used to perform the
integration then the answer is
which gives the correct result but uses the a specialized
hypergeometric function.
Remark
1.2 Mathematica 7 will get the
following formula for the integral
![]()
![]()
Remark 2. If
the computer algebra Maple is used to perform the integration then
the answer is
.
Summary of Formulas. The following four mapping of the upper half-plane will produce the same results.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell