Solution 5.
Solution. For the real
function
and
, we
have
![]()
.
This implies that
.
Therefore, the real function
is continuous at
.
The
complex
function
has
an essential singularity at the origin.
Use the fact that
, and
express this function as a Laurent
series.
Use the substitution
and
get
Then apply Definition
7.5 to conclude that
has
an essential singularity at the origin.
Therefore, the complex function
is
not continuous at
.
We are done.
Aside. We can let Mathematica double check our work.
The limit for the real
function
is
.
There is not a unique limit for the
complex function
as
.
For example, the limits along the real and imaginary axis are
different:
,
but
.
We can set
then
.
Now the limit along the imaginary axis is easier to compute
Therefore, the complex function
is
not continuous at
.
![[Graphics:../Images/TaylorLaurentApplicationModHome_gr_302.gif]](../Images/TaylorLaurentApplicationModHome_gr_302.gif)
The
graphs of
and
.
![[Graphics:../Images/TaylorLaurentApplicationModHome_gr_306.gif]](../Images/TaylorLaurentApplicationModHome_gr_306.gif)
A
plot for
. A
plot for
.
This solution is complements of the authors.
(c) 2008 John H. Mathews, Russell W. Howell